Question

Simplify this expression $e^{\psi\left(\frac12+\frac{i}{2\sqrt{3}}\right)+\psi\left(\frac12-\frac{i}{2\sqrt{3}}\right)}$?

score 120 · Answer 1 · 2026-03-25 20:36:26

120

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Simplify this expression $e^{\psi\left(\frac12+\frac{i}{2\sqrt{3}}\right)+\psi\left(\frac12-\frac{i}{2\sqrt{3}}\right)}$?

Published on 25 Mar 2026 - 20:36

score 50 · Answer 2 · 2026-03-25 17:35:38

50

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a limit containing a digamma function

Published on 25 Mar 2026 - 17:35

score 73 · Answer 3 · 2021-02-18 10:32:57

73

Views

prove an inequality containing digamma function

Published on 18 Feb 2021 - 10:32

score 42 · Answer 4 · 2021-02-18 15:59:11

42

Views

Monotony of $x\psi(x)$ and $x^2\psi(x)$ on the positive reals.

Published on 18 Feb 2021 - 15:59

score 245 · Answer 5 · 2021-03-11 03:42:43

245

Views

Closed form of $\sum_{m=1}^{\infty} \frac{(-1)^mH_{\frac{3m}{4}}}{3m}$

Published on 11 Mar 2021 - 3:42

score 268 · Answer 6 · 2021-03-19 18:29:57

268

Views

Integration using digamma functions

Published on 19 Mar 2021 - 18:29

score 573 · Answer 7 · 2026-03-25 07:15:11

573

Views

Beautiful monster: Catalan's constant and the Digamma function

Published on 25 Mar 2026 - 7:15

score 55 · Answer 8 · 2021-03-31 20:27:59

55

Views

Complex Limit containing gamma and digamma function:

Published on 31 Mar 2021 - 20:27

score 231 · Answer 9 · 2021-04-19 09:34:01

231

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exponential distribution and the gamma function

Published on 19 Apr 2021 - 9:34

score 99 · Answer 10 · 2021-05-03 05:24:13

99

Views

Show $\Psi\left(n + \frac{1}{2}\right) - \Psi(n + 1) = -2\int_0^1\frac{x^{2n}}{1 + x}\,dx $

Published on 03 May 2021 - 5:24

score 203 · Answer 11 · 2021-05-10 16:30:16

203

Views

How do you interpret the infinite activity property of variance gamma process?

Published on 10 May 2021 - 16:30

score 404 · Answer 12 · 2021-05-14 22:25:17

404

Views

How to write a limit in terms of finite summation

Published on 14 May 2021 - 22:25

score 377 · Answer 13 · 2026-03-25 19:04:53

377

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Evaluation of $\sum_{n=1}^{\infty}\frac{1}{n(2n+1)}=2-2\ln(2)$

Published on 25 Mar 2026 - 19:04

score 275 · Answer 14 · 2021-05-26 14:10:26

275

Views

Compute the double sum $\sum_{n, m>0, n \neq m} \frac{1}{n\left(m^{2}-n^{2}\right)}=\frac{3}{4} \zeta(3)$

Published on 26 May 2021 - 14:10

score 121 · Answer 15 · 2021-05-27 22:53:54

121

Views

How do you derive the "reflection formula" for the digamma function?

Published on 27 May 2021 - 22:53

List Question

Simplify this expression $e^{\psi\left(\frac12+\frac{i}{2\sqrt{3}}\right)+\psi\left(\frac12-\frac{i}{2\sqrt{3}}\right)}$?

a limit containing a digamma function

prove an inequality containing digamma function

Monotony of $x\psi(x)$ and $x^2\psi(x)$ on the positive reals.

Closed form of $\sum_{m=1}^{\infty} \frac{(-1)^mH_{\frac{3m}{4}}}{3m}$

Integration using digamma functions

Beautiful monster: Catalan's constant and the Digamma function

Complex Limit containing gamma and digamma function:

exponential distribution and the gamma function

Show $\Psi\left(n + \frac{1}{2}\right) - \Psi(n + 1) = -2\int_0^1\frac{x^{2n}}{1 + x}\,dx $

How do you interpret the infinite activity property of variance gamma process?

How to write a limit in terms of finite summation

Evaluation of $\sum_{n=1}^{\infty}\frac{1}{n(2n+1)}=2-2\ln(2)$

Compute the double sum $\sum_{n, m>0, n \neq m} \frac{1}{n\left(m^{2}-n^{2}\right)}=\frac{3}{4} \zeta(3)$

How do you derive the "reflection formula" for the digamma function?

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