Question

On a curious equation regarding odd perfect numbers

score 115 · Answer 1 · 2026-03-27 10:17:03

115

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On a curious equation regarding odd perfect numbers

Published on 27 Mar 2026 - 10:17

score 189 · Answer 2 · 2026-03-27 10:07:01

189

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Why does an odd perfect number seemingly "violate" basic inequality rules?

Published on 27 Mar 2026 - 10:07

score 74 · Answer 3 · 2020-12-05 10:14:52

74

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Question about a set of distinct odd integers and their least common multiple

Published on 05 Dec 2020 - 10:14

score 127 · Answer 4 · 2026-03-27 14:57:43

127

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Is every multiperfect number also pseudoperfect?

Published on 27 Mar 2026 - 14:57

score 47 · Answer 5 · 2020-12-15 00:50:15

47

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Divisor sum of totient function squared

Published on 15 Dec 2020 - 0:50

score 327 · Answer 6 · 2020-12-17 00:14:16

327

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Question on sums of products of divisors

Published on 17 Dec 2020 - 0:14

score 110 · Answer 7 · 2020-12-19 23:56:44

110

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Question on sums of products of divisors (cont.)

Published on 19 Dec 2020 - 23:56

score 271 · Answer 8 · 2026-03-27 13:10:49

271

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If $q^k n^2$ is an odd perfect number with special prime $q$, is $\sigma(q^k)$ coprime to $\sigma(n^2)$?

Published on 27 Mar 2026 - 13:10

score 57 · Answer 9 · 2026-03-26 14:34:49

57

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When is the number of Divisors of a Number equivalent to one of its Factors?

Published on 26 Mar 2026 - 14:34

score 66 · Answer 10 · 2021-01-04 07:28:55

Property of a divisor function, $\lim_{n\to\infty} \frac{\rho(n, n)}{n^2}=1-{\pi^2\over12}$ where $\rho(n, k):=\sum_{i=1}^k{(n\mod i)}$

score 254 · Answer 11 · 2026-03-27 13:10:31

254

Views

Revisiting questions 3888565 and 3894925

Published on 27 Mar 2026 - 13:10

score 267 · Answer 12 · 2026-03-27 13:10:49

267

Views

What numerical lower bound on the index of an odd perfect number is implied by the results in F.-J. Chen and Y.-G. Chen's 2014 paper?

Published on 27 Mar 2026 - 13:10

score 74 · Answer 13 · 2026-03-25 14:34:39

74

Views

coefficient $[q^n]\sum_{m\ge1}\frac{q^{\alpha m}}{1-q^{\beta m}}$ where $0<\alpha<\beta$

Published on 25 Mar 2026 - 14:34

score 439 · Answer 14 · 2026-03-27 13:10:49

439

Views

Does the following lower bound improve on $I(q^k) + I(n^2) > 3 - \frac{q-2}{q(q-1)}$, where $q^k n^2$ is an odd perfect number?

Published on 27 Mar 2026 - 13:10

score 169 · Answer 15 · 2021-01-28 14:06:23

169

Views

Prove that $\sigma(am) < \sigma(am + 1)$ for infinitely many positive integers $m$

Published on 28 Jan 2021 - 14:06

List Question

On a curious equation regarding odd perfect numbers

Why does an odd perfect number seemingly "violate" basic inequality rules?

Question about a set of distinct odd integers and their least common multiple

Is every multiperfect number also pseudoperfect?

Divisor sum of totient function squared

Question on sums of products of divisors

Question on sums of products of divisors (cont.)

If $q^k n^2$ is an odd perfect number with special prime $q$, is $\sigma(q^k)$ coprime to $\sigma(n^2)$?

When is the number of Divisors of a Number equivalent to one of its Factors?

Property of a divisor function, $\lim_{n\to\infty} \frac{\rho(n, n)}{n^2}=1-{\pi^2\over12}$ where $\rho(n, k):=\sum_{i=1}^k{(n\mod i)}$

Revisiting questions 3888565 and 3894925

What numerical lower bound on the index of an odd perfect number is implied by the results in F.-J. Chen and Y.-G. Chen's 2014 paper?

coefficient $[q^n]\sum_{m\ge1}\frac{q^{\alpha m}}{1-q^{\beta m}}$ where $0<\alpha<\beta$

Does the following lower bound improve on $I(q^k) + I(n^2) > 3 - \frac{q-2}{q(q-1)}$, where $q^k n^2$ is an odd perfect number?

Prove that $\sigma(am) < \sigma(am + 1)$ for infinitely many positive integers $m$

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