Question

Analyse Equicontinuity (uniform continuity) of a function $ \frac{\sin(x)}{x},\; x > 0 $

score 65 · Answer 1 · 2018-12-09 17:31:32

65

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Analyse Equicontinuity (uniform continuity) of a function $ \frac{\sin(x)}{x},\; x > 0 $

Published on 09 Dec 2018 - 17:31

score 130 · Answer 2 · 2018-12-15 16:21:35

130

Views

Sequence of continuous function converging pointwise to continuous function is equicontinuous?

Published on 15 Dec 2018 - 16:21

score 434 · Answer 3 · 2019-01-05 07:54:21

434

Views

Does uniform continuity on a compact subset imply equicontinuity?

Published on 05 Jan 2019 - 7:54

score 36 · Answer 4 · 2019-01-08 15:32:10

36

Views

Deriving an inequality for a set of functions that have equi-Lipschitz first derivatives.

Published on 08 Jan 2019 - 15:32

score 152 · Answer 5 · 2019-01-09 01:40:08

152

Views

Family of uniformly continuous functions, pointwise equicontinuous but is not uniformy equicontinuous.

Published on 09 Jan 2019 - 1:40

score 513 · Answer 6 · 2019-01-10 17:11:40

513

Views

continuous-sup property and equicontinuous set.

Published on 10 Jan 2019 - 17:11

score 196 · Answer 7 · 2019-01-11 14:39:28

196

Views

Sequence of smooth equicontinuous functions with unbounded derivatives

Published on 11 Jan 2019 - 14:39

score 276 · Answer 8 · 2019-01-14 06:07:24

276

Views

Equicontinuous homeomorphism and compact metric

Published on 14 Jan 2019 - 6:07

score 86 · Answer 9 · 2019-01-21 21:42:13

86

Views

Proof of equicontinuity via uniform convergence

Published on 21 Jan 2019 - 21:42

score 219 · Answer 10 · 2019-01-24 22:14:35

219

Views

Show that this operator is not compact using Arzela-Ascoli

Published on 24 Jan 2019 - 22:14

score 206 · Answer 11 · 2019-01-25 14:00:00

206

Views

Compact operator by proving Ascoli-Arzelà

Published on 25 Jan 2019 - 14:00

score 70 · Answer 12 · 2019-01-28 14:34:20

70

Views

Show that a sequence admits converging subsequence

Published on 28 Jan 2019 - 14:34

score 116 · Answer 13 · 2019-01-29 12:16:34

116

Views

Existence of Solution for Initial value Problem $y'(t)=\cos(ty), t>0$ and $y(0)=\frac{1}{n}, n\in\mathbb{N}$ using Ascoli Arzela

Published on 29 Jan 2019 - 12:16

score 130 · Answer 14 · 2019-01-30 07:55:38

130

Views

Sequence of solutions to a continuous ordinary differential equation in $\mathbb R^n$ has a convergent subsequence

Published on 30 Jan 2019 - 7:55

score 1.1k · Answer 15 · 2019-02-01 04:48:50

1.1k

Views

Uniformly convergent subsequence of a uniformly bounded family of functions

Published on 01 Feb 2019 - 4:48

List Question

Analyse Equicontinuity (uniform continuity) of a function $ \frac{\sin(x)}{x},\; x > 0 $

Sequence of continuous function converging pointwise to continuous function is equicontinuous?

Does uniform continuity on a compact subset imply equicontinuity?

Deriving an inequality for a set of functions that have equi-Lipschitz first derivatives.

Family of uniformly continuous functions, pointwise equicontinuous but is not uniformy equicontinuous.

continuous-sup property and equicontinuous set.

Sequence of smooth equicontinuous functions with unbounded derivatives

Equicontinuous homeomorphism and compact metric

Proof of equicontinuity via uniform convergence

Show that this operator is not compact using Arzela-Ascoli

Compact operator by proving Ascoli-Arzelà

Show that a sequence admits converging subsequence

Existence of Solution for Initial value Problem $y'(t)=\cos(ty), t>0$ and $y(0)=\frac{1}{n}, n\in\mathbb{N}$ using Ascoli Arzela

Sequence of solutions to a continuous ordinary differential equation in $\mathbb R^n$ has a convergent subsequence

Uniformly convergent subsequence of a uniformly bounded family of functions

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