Is the parity of error function enough to show :$\int_{-l}^{l} \exp ({\operatorname{-x^2erf(x)})dx=\int_{-l}^{l} \exp({\operatorname{x^2erf}}(x)})dx$?

score 24 · Answer 8 · 2026-04-15 21:32:27

24

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Why this :$I(x)=\int_{-x}^x {0.5(\exp({-t² {\operatorname{erf}(t^2)}})}dt$ is not error function for $|x| >3$?

Published on 15 Apr 2026 - 21:32

score 276 · Answer 9 · 2026-04-14 07:42:19

276

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The Fourier transform of $\frac{\text{erf}(\omega x)}{x}$

Published on 14 Apr 2026 - 7:42

score 2.3k · Answer 10 · 2026-04-14 17:51:58

2.3k

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Mean Absolute Error (MAE) equal or more than 1.

Published on 14 Apr 2026 - 17:51

score 226 · Answer 11 · 2026-04-16 02:14:19

226

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Nice result that I can't prove: $\int_{-2}^{2} \tan^{-1} \bigg( \exp(-x²\text{erf}(x)) \bigg) \;dx=\pi$

Published on 16 Apr 2026 - 2:14

score 106 · Answer 12 · 2026-05-10 15:10:49

106

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Solve an equation involving the error function

Published on 10 May 2026 - 15:10

score 339 · Answer 13 · 2026-05-10 13:44:53

339

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Laplace Transform of Complementary Error Function

Published on 10 May 2026 - 13:44

score 230 · Answer 14 · 2026-05-10 16:59:54

230

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Seeking Methods to solve $F\left(\alpha\right) = \int_{0}^{1} x^\alpha \arcsin(x)\:dx$

Published on 10 May 2026 - 16:59

score 292 · Answer 15 · 2026-04-15 18:40:48

292

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On $\int_0^\infty \frac{\exp(-x^2)}{1+x^2}dx=\frac{\pi e}2\text{erfc}(1)$

Published on 15 Apr 2026 - 18:40

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Is the parity of error function enough to show :$\int_{-l}^{l} \exp ({\operatorname{-x^2erf(x)})dx=\int_{-l}^{l} \exp({\operatorname{x^2erf}}(x)})dx$?

Why this :$I(x)=\int_{-x}^x {0.5(\exp({-t² {\operatorname{erf}(t^2)}})}dt$ is not error function for $|x| >3$?

The Fourier transform of $\frac{\text{erf}(\omega x)}{x}$

Mean Absolute Error (MAE) equal or more than 1.

Nice result that I can't prove: $\int_{-2}^{2} \tan^{-1} \bigg( \exp(-x²\text{erf}(x)) \bigg) \;dx=\pi$

Solve an equation involving the error function

Laplace Transform of Complementary Error Function

Seeking Methods to solve $F\left(\alpha\right) = \int_{0}^{1} x^\alpha \arcsin(x)\:dx$

On $\int_0^\infty \frac{\exp(-x^2)}{1+x^2}dx=\frac{\pi e}2\text{erfc}(1)$

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