Question

How to use Stirling's approximation for $(2n)!$ to get the simplified version of the formula?

score 3.1k · Answer 1 · 2017-07-23 08:11:31

3.1k

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How to use Stirling's approximation for $(2n)!$ to get the simplified version of the formula?

Published on 23 Jul 2017 - 8:11

score 703 · Answer 2 · 2017-07-26 08:37:11

703

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Find the remainder when $3(12!)-15(11!)$ divides $22(11!)+22!$

Published on 26 Jul 2017 - 8:37

score 99 · Answer 3 · 2017-07-27 05:21:02

99

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Factorial Trailing zeroes intuition

Published on 27 Jul 2017 - 5:21

score 216 · Answer 4 · 2026-03-25 17:17:22

216

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Finding large prime gaps without using brute force

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score 62 · Answer 5 · 2017-07-30 09:35:30

62

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Help with proof that $n! \geqslant e(\frac{n}{e})^n$

Published on 30 Jul 2017 - 9:35

score 1k · Answer 6 · 2017-07-31 08:45:59

1k

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what is the value x if x factorial equals zero? (x!=0)

Published on 31 Jul 2017 - 8:45

score 207 · Answer 7 · 2017-07-31 14:34:17

207

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Prove that $(2n)!$ is always divisible by $n!\cdot(n+1)!$

Published on 31 Jul 2017 - 14:34

score 1.2k · Answer 8 · 2017-07-31 16:17:59

1.2k

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To prove $n\binom{2n-1}{n-1}$ is divisible by $n(2n-1)$

Published on 31 Jul 2017 - 16:17

score 51 · Answer 9 · 2017-08-01 06:27:18

51

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How to find out $ k $ in this problem

Published on 01 Aug 2017 - 6:27

score 158 · Answer 10 · 2026-04-03 11:41:20

158

Views

How to get decimal answers of a factorial

Published on 03 Apr 2026 - 11:41

score 24 · Answer 11 · 2017-08-01 14:51:25

24

Views

Amount of combinations out of seven when only five can be in at one time

Published on 01 Aug 2017 - 14:51

score 202 · Answer 12 · 2026-03-29 16:57:15

202

Views

q-shifted factorial

Published on 29 Mar 2026 - 16:57

score 211 · Answer 13 · 2017-08-07 18:14:48

211

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For which integers is $i,j \geq 1$ exists an integer $k \geq 0$, such that $\frac{(i+j-1)!}{i!(j-1)!}=2^k$

Published on 07 Aug 2017 - 18:14

score 143 · Answer 14 · 2026-04-07 19:34:57

143

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Is it possible to calculate $\sum_{i=1}^n \ln(x_i!)$, given $\sum_{i=1}^n x_i$

Published on 07 Apr 2026 - 19:34

score 113 · Answer 15 · 2017-08-10 23:55:12

113

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Can you help to solve this $n! \geq n^3$ by mathematical induction?

Published on 10 Aug 2017 - 23:55

List Question

How to use Stirling's approximation for $(2n)!$ to get the simplified version of the formula?

Find the remainder when $3(12!)-15(11!)$ divides $22(11!)+22!$

Factorial Trailing zeroes intuition

Finding large prime gaps without using brute force

Help with proof that $n! \geqslant e(\frac{n}{e})^n$

what is the value x if x factorial equals zero? (x!=0)

Prove that $(2n)!$ is always divisible by $n!\cdot(n+1)!$

To prove $n\binom{2n-1}{n-1}$ is divisible by $n(2n-1)$

How to find out $ k $ in this problem

How to get decimal answers of a factorial

Amount of combinations out of seven when only five can be in at one time

q-shifted factorial

For which integers is $i,j \geq 1$ exists an integer $k \geq 0$, such that $\frac{(i+j-1)!}{i!(j-1)!}=2^k$

Is it possible to calculate $\sum_{i=1}^n \ln(x_i!)$, given $\sum_{i=1}^n x_i$

Can you help to solve this $n! \geq n^3$ by mathematical induction?

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