Question

For $x_1,x_2,x_3\in\mathbb R$ that $x_1+x_2+x_3=0$ show that $\sum_{i=1}^{3}\frac{1}{x^2_i} =({\sum_{i=1}^{3}\frac{1}{x_i}})^2$

score 167 · Answer 1 · 2012-02-29 11:52:35

For $x_1,x_2,x_3\in\mathbb R$ that $x_1+x_2+x_3=0$ show that $\sum_{i=1}^{3}\frac{1}{x^2_i} =({\sum_{i=1}^{3}\frac{1}{x_i}})^2$

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List Question

For $x_1,x_2,x_3\in\mathbb R$ that $x_1+x_2+x_3=0$ show that $\sum_{i=1}^{3}\frac{1}{x^2_i} =({\sum_{i=1}^{3}\frac{1}{x_i}})^2$

What are the steps for factorizing $1 - ab - cd + abcd$?

Factor $14x^2 - 17x + 5$.

How to express $\frac{x^3+4x^2-1}{(x^2+1)^2}$ as a polynomial plus a proper fraction, using long division?

Beginners question: Factorised expression, not sure how book got the answer

Could G. H. Hardy make a product of two primes so big he couldn't find out which?

What are the specifics and the possible outputs of Pollard's Rho algorithm?

Help with basic high school math. What happens to $j^2$?

Factors of a polynomial in several variables

Notation : What is the meaning of the (mod n) in factoring algorithms?

Factorize polynomial over $GF(3)$

Quick way to find the highest multiplicity of a divisor of a number?

Factoring $y$ out of $y^2 + e^y$ possible?

Basic factoring problem.

Factoring polynomials and equating coefficients

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