Question

Factorize: $1-\frac{1}{6}z^{-1}-\frac{1}{3}z^{-2}$ into $(1-az^{-1})(1-bz^{-1})$

score 45 · Answer 1 · 2026-04-17 08:11:16

45

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Factorize: $1-\frac{1}{6}z^{-1}-\frac{1}{3}z^{-2}$ into $(1-az^{-1})(1-bz^{-1})$

Published on 17 Apr 2026 - 8:11

score 30 · Answer 2 · 2026-04-16 04:48:22

30

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Is there a name for the decomposition of $m^1w^1-m^0w^0$ into $(m^1-m^0)w^0+(w^1-w^0)m^0+(m^1-m^0)(w^1-w^0)$?

Published on 16 Apr 2026 - 4:48

score 72 · Answer 3 · 2026-04-09 15:00:05

72

Views

How does $\frac{k^2(k+1)^2}{4} + (k+1)^3$ become $\frac{(k+1)^2(k+2)^2}{4}$?

Published on 09 Apr 2026 - 15:00

score 110 · Answer 4 · 2026-04-14 01:37:56

110

Views

Formula for $x^n+1$

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score 54 · Answer 5 · 2026-04-09 10:57:26

54

Views

Showing that a function has at least three roots

Published on 09 Apr 2026 - 10:57

score 56 · Answer 6 · 2026-04-14 07:17:16

56

Views

Equation with polynomial with integer coeficients.

Published on 14 Apr 2026 - 7:17

score 287 · Answer 7 · 2026-04-14 07:25:46

287

Views

Maximal degree of irreducible polynomials

Published on 14 Apr 2026 - 7:25

score 70 · Answer 8 · 2026-04-15 20:19:18

70

Views

Author calls factors $(x+1-\sqrt2)(x+1+\sqrt2)$ "rational so far as $x$ is concerned". What does this mean?

Published on 15 Apr 2026 - 20:19

score 113 · Answer 9 · 2026-04-14 17:48:32

113

Views

How to differentiate the function, $7x^5\sqrt{3x^4-5x^2}$

Published on 14 Apr 2026 - 17:48

score 130 · Answer 10 · 2026-04-17 00:37:17

130

Views

Factorisation of $X^n-a$ in $\mathbb{F}_p$

Published on 17 Apr 2026 - 0:37

score 108 · Answer 11 · 2026-04-14 07:22:53

108

Views

Binary Galois field, test for irreducible polynomial in NASA paper

Published on 14 Apr 2026 - 7:22

score 50 · Answer 12 · 2026-04-17 15:57:14

50

Views

Proof of $f(x)\in I\Leftrightarrow f(i)=0\Leftrightarrow f(x)=q(x)(x^2+1) (q(x)\in\mathbb{R}[x])$.

Published on 17 Apr 2026 - 15:57

score 290 · Answer 13 · 2026-04-16 03:47:15

290

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Prove that $z^{2n} - 2 a^n z^n \cos (nθ) + a^{2n}=\prod_{k=0}^{n-1}\left[z^2-2az\cos\left(\theta+\frac{2\pi k}{n}\right)+a\right]$

Published on 16 Apr 2026 - 3:47

score 90 · Answer 14 · 2026-04-11 14:11:36

90

Views

Numbers for Testing Integer Factoring Algorithms

Published on 11 Apr 2026 - 14:11

score 28 · Answer 15 · 2026-04-12 13:59:17

28

Views

Tips factoring formula to form of $\frac{1}{f(x)}=\frac{1}{g(x)}+\frac{1}{h(x)}+...?$

Published on 12 Apr 2026 - 13:59

List Question

Factorize: $1-\frac{1}{6}z^{-1}-\frac{1}{3}z^{-2}$ into $(1-az^{-1})(1-bz^{-1})$

Is there a name for the decomposition of $m^1w^1-m^0w^0$ into $(m^1-m^0)w^0+(w^1-w^0)m^0+(m^1-m^0)(w^1-w^0)$?

How does $\frac{k^2(k+1)^2}{4} + (k+1)^3$ become $\frac{(k+1)^2(k+2)^2}{4}$?

Formula for $x^n+1$

Showing that a function has at least three roots

Equation with polynomial with integer coeficients.

Maximal degree of irreducible polynomials

Author calls factors $(x+1-\sqrt2)(x+1+\sqrt2)$ "rational so far as $x$ is concerned". What does this mean?

How to differentiate the function, $7x^5\sqrt{3x^4-5x^2}$

Factorisation of $X^n-a$ in $\mathbb{F}_p$

Binary Galois field, test for irreducible polynomial in NASA paper

Proof of $f(x)\in I\Leftrightarrow f(i)=0\Leftrightarrow f(x)=q(x)(x^2+1) (q(x)\in\mathbb{R}[x])$.

Prove that $z^{2n} - 2 a^n z^n \cos (nθ) + a^{2n}=\prod_{k=0}^{n-1}\left[z^2-2az\cos\left(\theta+\frac{2\pi k}{n}\right)+a\right]$

Numbers for Testing Integer Factoring Algorithms

Tips factoring formula to form of $\frac{1}{f(x)}=\frac{1}{g(x)}+\frac{1}{h(x)}+...?$

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