Question

Kernel of surjective map from rank two module is free and rank 1.

score 115 · Answer 1 · 2026-03-26 07:34:55

115

Views

Kernel of surjective map from rank two module is free and rank 1.

Published on 26 Mar 2026 - 7:34

score 56 · Answer 2 · 2020-10-30 12:25:52

56

Views

Tensor product of free R modules is $R^{mn}$

Published on 30 Oct 2020 - 12:25

score 72 · Answer 3 · 2020-10-30 22:49:55

72

Views

Free module is a right $R$-module with scaling operation.

Published on 30 Oct 2020 - 22:49

score 390 · Answer 4 · 2020-11-17 14:23:19

390

Views

Higher Ext vanish iff module is free

Published on 17 Nov 2020 - 14:23

score 430 · Answer 5 · 2020-12-09 13:08:41

430

Views

Index of submodule generated by multiplication by one element of free $\mathbb{Z}$-module

Published on 09 Dec 2020 - 13:08

score 70 · Answer 6 · 2020-12-13 15:36:17

70

Views

Existence of epimorphism from a Ring to a Module

Published on 13 Dec 2020 - 15:36

score 124 · Answer 7 · 2020-12-17 08:12:38

124

Views

Is $\bigoplus_{x \in X} \mathbb{Z}$ reflexive?

Published on 17 Dec 2020 - 8:12

score 183 · Answer 8 · 2020-12-19 12:47:50

183

Views

Prove, using category theory, that every base of free $R$-module ($R$ a conmutative ring) have the same cardinality

Published on 19 Dec 2020 - 12:47

score 481 · Answer 9 · 2026-02-23 11:27:19

481

Views

Smith normal form and elementary divisors

Published on 23 Feb 2026 - 11:27

score 110 · Answer 10 · 2026-02-23 11:33:06

110

Views

If $f:\mathbb{Z}^m\to\mathbb{Z}^m$ is a module homomorphism, then $\mathbb{Z}^m/\operatorname{im}(f)$ is a finite abelian group

Published on 23 Feb 2026 - 11:33

score 55 · Answer 11 · 2020-12-21 09:27:45

55

Views

How decomposes an $R[x]/(x^n)$-module which is free of finite rank over $R$?

Published on 21 Dec 2020 - 9:27

score 193 · Answer 12 · 2026-03-26 16:06:22

193

Views

How to find a syzygy module is graded free module over R?

Published on 26 Mar 2026 - 16:06

score 140 · Answer 13 · 2020-12-30 18:45:31

140

Views

Confused about Tensor Product of R-modules

Published on 30 Dec 2020 - 18:45

score 370 · Answer 14 · 2021-01-02 15:06:37

370

Views

The structure of the quotients of free modules

Published on 02 Jan 2021 - 15:06

score 88 · Answer 15 · 2021-01-04 10:58:58

88

Views

Is a bounded complex of projective $R$-modules of finite type quasi-isomorphic to a bounded complex of free $R$-modules of finite type?

Published on 04 Jan 2021 - 10:58

List Question

Kernel of surjective map from rank two module is free and rank 1.

Tensor product of free R modules is $R^{mn}$

Free module is a right $R$-module with scaling operation.

Higher Ext vanish iff module is free

Index of submodule generated by multiplication by one element of free $\mathbb{Z}$-module

Existence of epimorphism from a Ring to a Module

Is $\bigoplus_{x \in X} \mathbb{Z}$ reflexive?

Prove, using category theory, that every base of free $R$-module ($R$ a conmutative ring) have the same cardinality

Smith normal form and elementary divisors

If $f:\mathbb{Z}^m\to\mathbb{Z}^m$ is a module homomorphism, then $\mathbb{Z}^m/\operatorname{im}(f)$ is a finite abelian group

How decomposes an $R[x]/(x^n)$-module which is free of finite rank over $R$?

How to find a syzygy module is graded free module over R?

Confused about Tensor Product of R-modules

The structure of the quotients of free modules

Is a bounded complex of projective $R$-modules of finite type quasi-isomorphic to a bounded complex of free $R$-modules of finite type?

Trending Questions

Popular # Hahtags

Popular Questions