Question

tensor product of non free modules which is free

score 761 · Answer 1 · 2026-04-13 19:03:08

761

Views

tensor product of non free modules which is free

Published on 13 Apr 2026 - 19:03

score 36 · Answer 2 · 2026-05-10 17:01:09

36

Views

Question about isomorphism of direct sums (Step needed to show uniqueness of Elementary Divisors Theorem)

Published on 10 May 2026 - 17:01

score 421 · Answer 3 · 2026-04-15 21:41:09

421

Views

Noncommutative rings, matrices and homomorphisms of free modules

Published on 15 Apr 2026 - 21:41

score 487 · Answer 4 · 2026-04-13 01:39:09

487

Views

Decomposition of an abelian group subject to certain relations

Published on 13 Apr 2026 - 1:39

score 44 · Answer 5 · 2026-05-05 13:50:04

44

Views

About finitely presented algebras and free product

Published on 05 May 2026 - 13:50

score 76 · Answer 6 · 2026-04-13 19:33:18

76

Views

Linear independent set of the right cardinality is a basis.

Published on 13 Apr 2026 - 19:33

score 515 · Answer 7 · 2026-04-12 22:09:50

515

Views

Step in Bourbaki Commutative algebra exercise

Published on 12 Apr 2026 - 22:09

score 96 · Answer 8 · 2026-04-13 23:11:14

96

Views

Expression for the sum of submodules of a free $\Bbb{Z}$-module

Published on 13 Apr 2026 - 23:11

score 175 · Answer 9 · 2026-05-10 20:52:10

175

Views

GAP — compute kernel of a matrix with coefficients in a finite ring

Published on 10 May 2026 - 20:52

score 530 · Answer 10 · 2026-04-16 14:42:49

530

Views

For $F$ a finitely generated free $R$-module, prove $F \cong \text{Hom}_R (F, R)$

Published on 16 Apr 2026 - 14:42

score 217 · Answer 11 · 2026-04-11 17:36:33

217

Views

An equivalent definition of division rings (in module theory)

Published on 11 Apr 2026 - 17:36

score 416 · Answer 12 · 2026-05-10 22:02:46

416

Views

Extension of linearly independent set to a basis of a free module over a quotient of a Dedekind domain

Published on 10 May 2026 - 22:02

score 489 · Answer 13 · 2026-04-15 18:06:54

489

Views

Clarification: If $R$ is a ring, then $R^n\cong R^m$ as left $R$-modules if and only if they are also isomorphic as right $R$-modules.

Published on 15 Apr 2026 - 18:06

score 147 · Answer 14 · 2026-04-12 23:37:18

147

Views

Basis of a free algebra: linear independence of tensor powers

Published on 12 Apr 2026 - 23:37

score 603 · Answer 15 · 2026-05-10 20:08:25

603

Views

Every finitely generated module of a PID is a direct sum of a free module and of a torsion module

Published on 10 May 2026 - 20:08

List Question

tensor product of non free modules which is free

Question about isomorphism of direct sums (Step needed to show uniqueness of Elementary Divisors Theorem)

Noncommutative rings, matrices and homomorphisms of free modules

Decomposition of an abelian group subject to certain relations

About finitely presented algebras and free product

Linear independent set of the right cardinality is a basis.

Step in Bourbaki Commutative algebra exercise

Expression for the sum of submodules of a free $\Bbb{Z}$-module

GAP — compute kernel of a matrix with coefficients in a finite ring

For $F$ a finitely generated free $R$-module, prove $F \cong \text{Hom}_R (F, R)$

An equivalent definition of division rings (in module theory)

Extension of linearly independent set to a basis of a free module over a quotient of a Dedekind domain

Clarification: If $R$ is a ring, then $R^n\cong R^m$ as left $R$-modules if and only if they are also isomorphic as right $R$-modules.

Basis of a free algebra: linear independence of tensor powers

Every finitely generated module of a PID is a direct sum of a free module and of a torsion module

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