Question

Generalized Riesz theorem of operator value function

score 125 · Answer 1 · 2015-02-28 05:59:51

125

Views

Generalized Riesz theorem of operator value function

Published on 28 Feb 2015 - 5:59

score 90 · Answer 2 · 2015-02-28 13:36:11

90

Views

analitycs solutions to the equation $f'(x)=f(x)f(x-1)$

Published on 28 Feb 2015 - 13:36

score 180 · Answer 3 · 2015-02-28 13:38:36

180

Views

Show that f is linear

Published on 28 Feb 2015 - 13:38

score 558 · Answer 4 · 2015-02-28 14:27:44

558

Views

Monotonic additive function. I need to show it's linear

Published on 28 Feb 2015 - 14:27

score 1.1k · Answer 5 · 2015-03-01 15:09:38

1.1k

Views

Find $f(x)$ satisfy $f(2x)=2f(x)+x$

Published on 01 Mar 2015 - 15:09

score 264 · Answer 6 · 2015-03-01 18:59:19

264

Views

Functional equation $ f(x)+f(x+1)=x$

Published on 01 Mar 2015 - 18:59

score 1.9k · Answer 7 · 2015-03-02 09:08:13

1.9k

Views

If $ f(x \cdot f(y) + f(x)) = y \cdot f(x) + x $, then $f(x)=x$

Published on 02 Mar 2015 - 9:08

score 96 · Answer 8 · 2015-03-02 15:21:02

What is the formula and the name of the mathematical-phenomenon seen at the ending of "Around the World in Eighty Days"?

score 328 · Answer 9 · 2015-03-03 16:05:42

328

Views

Can we describe all group isomorphisms from $(\mathbb R ,+)$ to $(\mathbb R^+ , .)$ ?

Published on 03 Mar 2015 - 16:05

score 4.4k · Answer 10 · 2015-03-07 00:24:46

The function $f : \mathbb{R} \rightarrow \mathbb{R}$ satisfies $f(x) f(y) - f(xy) = x + y$ for all $x$, $y \in \mathbb{R}$. Find $f(x)$.

score 2.1k · Answer 11 · 2015-03-07 14:24:40

2.1k

Views

Find all real functions that satisfy the functional equations $f(x+y) = f(x) + f(y)$ and $f(xy)=f(x)\,f(y)$

Published on 07 Mar 2015 - 14:24

score 67 · Answer 12 · 2015-03-09 03:24:36

67

Views

Solving the functional equation $f(x)=f(f(x-p))+q$

Published on 09 Mar 2015 - 3:24

score 64 · Answer 13 · 2015-03-10 12:16:09

64

Views

What function satisfies the following equation?

Published on 10 Mar 2015 - 12:16

score 116 · Answer 14 · 2015-03-10 23:38:15

116

Views

Continuous, 1-periodic $f$ with $f(x+y) = f(x) f(y)$ for $x, y \in \mathbb{R}$

Published on 10 Mar 2015 - 23:38

score 669 · Answer 15 · 2015-03-11 05:26:27

669

Views

Does there exist a function such that $f(a)f(b)=f(a^2b^2)?$

Published on 11 Mar 2015 - 5:26

List Question

Generalized Riesz theorem of operator value function

analitycs solutions to the equation $f'(x)=f(x)f(x-1)$

Show that f is linear

Monotonic additive function. I need to show it's linear

Find $f(x)$ satisfy $f(2x)=2f(x)+x$

Functional equation $ f(x)+f(x+1)=x$

If $ f(x \cdot f(y) + f(x)) = y \cdot f(x) + x $, then $f(x)=x$

What is the formula and the name of the mathematical-phenomenon seen at the ending of "Around the World in Eighty Days"?

Can we describe all group isomorphisms from $(\mathbb R ,+)$ to $(\mathbb R^+ , .)$ ?

The function $f : \mathbb{R} \rightarrow \mathbb{R}$ satisfies $f(x) f(y) - f(xy) = x + y$ for all $x$, $y \in \mathbb{R}$. Find $f(x)$.

Find all real functions that satisfy the functional equations $f(x+y) = f(x) + f(y)$ and $f(xy)=f(x)\,f(y)$

Solving the functional equation $f(x)=f(f(x-p))+q$

What function satisfies the following equation?

Continuous, 1-periodic $f$ with $f(x+y) = f(x) f(y)$ for $x, y \in \mathbb{R}$

Does there exist a function such that $f(a)f(b)=f(a^2b^2)?$

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