Question

Deriving the series representation of the digamma function from the functional equation

score 380 · Answer 1 · 2013-07-17 04:52:36

380

Views

Deriving the series representation of the digamma function from the functional equation

Published on 17 Jul 2013 - 4:52

score 582 · Answer 2 · 2013-07-21 22:17:52

582

Views

Functional equation: $R(1/x)/x^2 = R(x) $

Published on 21 Jul 2013 - 22:17

score 90 · Answer 3 · 2013-07-24 07:20:23

90

Views

Functional equations very like the Taylor Series

Published on 24 Jul 2013 - 7:20

score 2.8k · Answer 4 · 2013-07-24 07:52:05

2.8k

Views

An example of the Sequential Quadratic Programming (SQP)

Published on 24 Jul 2013 - 7:52

score 948 · Answer 5 · 2013-07-26 14:59:44

948

Views

Cauchy functional equation over the complex field

Published on 26 Jul 2013 - 14:59

score 314 · Answer 6 · 2013-07-28 09:04:40

314

Views

Functional Equation - Am I right?

Published on 28 Jul 2013 - 9:04

score 126 · Answer 7 · 2013-07-30 07:54:09

126

Views

functional equation (conti-function $f(x)$)

Published on 30 Jul 2013 - 7:54

score 179 · Answer 8 · 2013-07-30 10:29:21

179

Views

Finding $f$ from the functional equation $f(x+y)=f(x) + f(y) + e^{x+y}(x+y)-xe^x-ye^y+2xy$

Published on 30 Jul 2013 - 10:29

score 156 · Answer 9 · 2013-07-31 04:31:06

156

Views

Finding all $f:\mathbb{R} \rightarrow \mathbb{R}$ s.t $f(x^2+f(y))=(x-y)^2f(x+y)$

Published on 31 Jul 2013 - 4:31

score 144 · Answer 10 · 2013-07-31 05:23:20

144

Views

Follow up to previous functional equation question: $f\big(x^2+f(y)\big)=(x-y)^2f(x+y)$

Published on 31 Jul 2013 - 5:23

score 126 · Answer 11 · 2013-08-03 12:00:26

126

Views

Solve the function equation $g^2(x)-g(x+1)-\dfrac{x^2+2x-6}{4}=0$

Published on 03 Aug 2013 - 12:00

score 180 · Answer 12 · 2013-08-04 16:46:54

180

Views

Any chance for a solution of $f[f(x)]=x^2+1$?

Published on 04 Aug 2013 - 16:46

score 189 · Answer 13 · 2013-08-05 09:29:52

189

Views

Find $f(x)$ from $2f'(x)-3f'(1/x)=x$

Published on 05 Aug 2013 - 9:29

score 182 · Answer 14 · 2026-03-28 10:16:47

182

Views

Unicity of solution to an integral equation

Published on 28 Mar 2026 - 10:16

score 4.6k · Answer 15 · 2013-08-07 11:45:22

$g(x+y)=g(x)g(y)$ for all $x,y \in\mathbb{R}$. If $g$ is continuous at $0$, prove that $g$ is continuous on $\mathbb{R}$

List Question

Deriving the series representation of the digamma function from the functional equation

Functional equation: $R(1/x)/x^2 = R(x) $

Functional equations very like the Taylor Series

An example of the Sequential Quadratic Programming (SQP)

Cauchy functional equation over the complex field

Functional Equation - Am I right?

functional equation (conti-function $f(x)$)

Finding $f$ from the functional equation $f(x+y)=f(x) + f(y) + e^{x+y}(x+y)-xe^x-ye^y+2xy$

Finding all $f:\mathbb{R} \rightarrow \mathbb{R}$ s.t $f(x^2+f(y))=(x-y)^2f(x+y)$

Follow up to previous functional equation question: $f\big(x^2+f(y)\big)=(x-y)^2f(x+y)$

Solve the function equation $g^2(x)-g(x+1)-\dfrac{x^2+2x-6}{4}=0$

Any chance for a solution of $f[f(x)]=x^2+1$?

Find $f(x)$ from $2f'(x)-3f'(1/x)=x$

Unicity of solution to an integral equation

$g(x+y)=g(x)g(y)$ for all $x,y \in\mathbb{R}$. If $g$ is continuous at $0$, prove that $g$ is continuous on $\mathbb{R}$

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