List questions from functional-equations

Published on 02 Jan 2018 - 8:51

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Method of solving functional equations

Published on 02 Jan 2018 - 11:22

90

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Solution of the functional equation $f(x)+f\left(\frac 1 x\right) = f(x)f\left(\frac 1 x\right)$

Published on 02 Jan 2018 - 15:40

74

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If a function is like $f(f(y))=a^2+y$, does it imply that $f$ is surjective?

Published on 02 Jan 2018 - 19:58

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Continuous $f$ such that $f(x)=f(x^2)$ is constant?

Published on 02 Jan 2018 - 23:37

255

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Finding functions satisfying $f(f(x))+f(x)+x=0$

Published on 03 Jan 2018 - 3:40

57

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Functions satisfying $f(x,y)f(y,z)=f(x,w)f(w,z)$

Published on 03 Jan 2018 - 11:20

152

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Classification of all functions satisfying $f$ such that $f(x)=f(x^2)$.

Published on 03 Jan 2018 - 12:55

2.5k

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Functional equation: what function is its inverse's reciprocal?

Published on 02 Apr 2026 - 15:11

508

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A possible converse to the Cayley-Hamilton theorem?

Published on 07 Jan 2018 - 0:01

95

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Find $f(2^{2017})$

Published on 07 Jan 2018 - 8:00

317

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Brachistochrone With Friction

Published on 08 Apr 2026 - 4:07

117

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Solutions to $f(x) + x\,f'(x)= f(2x)$

Published on 11 Jan 2018 - 17:38

315

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$f(a(x))=f(x)$ - functional equation

Published on 30 Jul 2010 - 2:37

1k

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Solution to $1-f(x) = f(-x)$

Published on 30 Jul 2010 - 8:23

List Question

Find all functions such that if $I$ open bounded interval then $f(I)$ is also open of same length

Method of solving functional equations

Solution of the functional equation $f(x)+f\left(\frac 1 x\right) = f(x)f\left(\frac 1 x\right)$

If a function is like $f(f(y))=a^2+y$, does it imply that $f$ is surjective?

Continuous $f$ such that $f(x)=f(x^2)$ is constant?

Finding functions satisfying $f(f(x))+f(x)+x=0$

Functions satisfying $f(x,y)f(y,z)=f(x,w)f(w,z)$

Classification of all functions satisfying $f$ such that $f(x)=f(x^2)$.

Functional equation: what function is its inverse's reciprocal?

A possible converse to the Cayley-Hamilton theorem?

Find $f(2^{2017})$

Brachistochrone With Friction

Solutions to $f(x) + x\,f'(x)= f(2x)$

$f(a(x))=f(x)$ - functional equation

Solution to $1-f(x) = f(-x)$

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