Question

Basic functional equation: $ f ( x y ) = f ( x ) + f ( y ) $

score 48 · Answer 1 · 2026-04-16 21:50:46

48

Views

Basic functional equation: $ f ( x y ) = f ( x ) + f ( y ) $

Published on 16 Apr 2026 - 21:50

score 89 · Answer 2 · 2026-04-15 17:56:19

89

Views

$f(x)$ such that $f(x)*f(f(x)+\frac{1}{x})=1$ and $f(x) > - \frac{1}{x}$ $ \forall$ $ x > 0$ and $f(x)$ is an injective function

Published on 15 Apr 2026 - 17:56

score 315 · Answer 3 · 2026-04-15 21:28:08

315

Views

Decide whether or not there exists $f(f(x))=5x-\lfloor 5x\rfloor$

Published on 15 Apr 2026 - 21:28

score 85 · Answer 4 · 2026-04-14 19:13:44

85

Views

Find a if $\sum_{K=1}^n f(a+K)=2n(33+n)$

Published on 14 Apr 2026 - 19:13

score 62 · Answer 5 · 2026-04-17 14:40:47

62

Views

$f(s,u) + f(u,t) = f(s,t)$ implies $f(s,t) = g(t)- g(s)$

Published on 17 Apr 2026 - 14:40

score 95 · Answer 6 · 2026-04-14 19:09:59

95

Views

$f(a+b) = f(a) \cdot f(b)$

Published on 14 Apr 2026 - 19:09

score 239 · Answer 7 · 2026-04-14 13:22:34

239

Views

A functional equation problem: $ \frac { f \left( f ( y ) ^ 2 + x y \right) } { f ( y ) } = f ( x ) + y $

Published on 14 Apr 2026 - 13:22

score 139 · Answer 8 · 2026-04-16 00:49:07

139

Views

Functional equation $f(x)+f(y)-f(x+y)=4f\left(\frac{x}{2}\right)f\left(\frac{y}{2}\right)f\left(\frac{x+y}{2}\right)$

Published on 16 Apr 2026 - 0:49

score 4.5k · Answer 9 · 2026-04-16 02:50:13

4.5k

Views

For which of the following functions is $f(a+b) = f(a) + f(b)$?

Published on 16 Apr 2026 - 2:50

score 178 · Answer 10 · 2026-04-14 16:23:38

178

Views

Function Equation Question Involving $f(xy)=f(x)f(y)-f(x+y)+1$

Published on 14 Apr 2026 - 16:23

score 109 · Answer 11 · 2026-04-17 04:48:01

109

Views

Function $f:\mathbb{R}\mapsto \mathbb{R}$ satisfying $f(f(x))=x+\lfloor x\rfloor$

Published on 17 Apr 2026 - 4:48

score 32 · Answer 12 · 2026-05-10 09:52:07

32

Views

Solutions to Functional Equation

Published on 10 May 2026 - 9:52

score 116 · Answer 13 · 2026-04-14 13:55:12

116

Views

Functional equation: $f(x^2+f(y))=y+f^2(x)$.

Published on 14 Apr 2026 - 13:55

score 92 · Answer 14 · 2026-04-09 10:51:01

92

Views

Proving that a functional equation is constant

Published on 09 Apr 2026 - 10:51

score 1k · Answer 15 · 2026-04-16 14:51:00

1k

Views

Recreational math: If $f(f(x))=e^x$, bound the integral $\int_0^1 f(x)dx$

Published on 16 Apr 2026 - 14:51

List Question

Basic functional equation: $ f ( x y ) = f ( x ) + f ( y ) $

$f(x)$ such that $f(x)*f(f(x)+\frac{1}{x})=1$ and $f(x) > - \frac{1}{x}$ $ \forall$ $ x > 0$ and $f(x)$ is an injective function

Decide whether or not there exists $f(f(x))=5x-\lfloor 5x\rfloor$

Find a if $\sum_{K=1}^n f(a+K)=2n(33+n)$

$f(s,u) + f(u,t) = f(s,t)$ implies $f(s,t) = g(t)- g(s)$

$f(a+b) = f(a) \cdot f(b)$

A functional equation problem: $ \frac { f \left( f ( y ) ^ 2 + x y \right) } { f ( y ) } = f ( x ) + y $

Functional equation $f(x)+f(y)-f(x+y)=4f\left(\frac{x}{2}\right)f\left(\frac{y}{2}\right)f\left(\frac{x+y}{2}\right)$

For which of the following functions is $f(a+b) = f(a) + f(b)$?

Function Equation Question Involving $f(xy)=f(x)f(y)-f(x+y)+1$

Function $f:\mathbb{R}\mapsto \mathbb{R}$ satisfying $f(f(x))=x+\lfloor x\rfloor$

Solutions to Functional Equation

Functional equation: $f(x^2+f(y))=y+f^2(x)$.

Proving that a functional equation is constant

Recreational math: If $f(f(x))=e^x$, bound the integral $\int_0^1 f(x)dx$

Trending Questions

Popular # Hahtags

Popular Questions