Does a simpler form exist for $\frac{\Re \left(\zeta(\frac12+it)\,\Gamma(\frac12+it)\right)}{\Im \left(\zeta(\frac12+it)\,\Gamma(\frac12+it)\right)}$?

score 83 · Answer 10 · 2026-03-25 12:50:57

83

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Is the following ratio of gamma functions increasing: $\frac{\Gamma(2n - \frac{1.25506n}{\ln n})}{\Gamma(n)^2}$?

Published on 25 Mar 2026 - 12:50

score 65 · Answer 11 · 2020-05-13 11:22:22

65

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Triple product identity for the Gamma function

Published on 13 May 2020 - 11:22

score 115 · Answer 12 · 2026-03-25 11:16:46

115

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Is this a correct way to use the digamma to analyze whether a ratio of gamma functions is increasing?

Published on 25 Mar 2026 - 11:16

score 70 · Answer 13 · 2020-05-14 16:20:56

70

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What could be said about $\Gamma(2n)=\Gamma(n)^n$?

Published on 14 May 2020 - 16:20

score 50 · Answer 14 · 2020-05-14 18:58:10

50

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Nested Gamma functions and $\lim_{n\to\infty} a_n=1$

Published on 14 May 2020 - 18:58

score 62 · Answer 15 · 2026-03-30 07:55:53

62

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Comparing a ratio of gamma functions to a simple polynomial

Published on 30 Mar 2026 - 7:55

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Does a simpler form exist for $\frac{\Re \left(\zeta(\frac12+it)\,\Gamma(\frac12+it)\right)}{\Im \left(\zeta(\frac12+it)\,\Gamma(\frac12+it)\right)}$?

Is the following ratio of gamma functions increasing: $\frac{\Gamma(2n - \frac{1.25506n}{\ln n})}{\Gamma(n)^2}$?

Triple product identity for the Gamma function

Is this a correct way to use the digamma to analyze whether a ratio of gamma functions is increasing?

What could be said about $\Gamma(2n)=\Gamma(n)^n$?

Nested Gamma functions and $\lim_{n\to\infty} a_n=1$

Comparing a ratio of gamma functions to a simple polynomial

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