Question

Write $\frac {1}{1+z^2}$ as a power series centered at $z_0=1$

score 2.9k · Answer 1 · 2015-12-10 12:30:38

2.9k

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Write $\frac {1}{1+z^2}$ as a power series centered at $z_0=1$

Published on 10 Dec 2015 - 12:30

score 1k · Answer 2 · 2026-02-23 09:30:43

1k

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Cauchy Product of two simple geometric series

Published on 23 Feb 2026 - 9:30

score 2.2k · Answer 3 · 2015-12-17 18:10:48

2.2k

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Area of circles inside an equilateral triangle compared to the area of the triangle itself.

Published on 17 Dec 2015 - 18:10

score 45 · Answer 4 · 2015-12-25 19:36:57

45

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How to show that partial sums of an infinite series can be written in a different form

Published on 25 Dec 2015 - 19:36

score 116 · Answer 5 · 2015-12-25 22:20:08

Determine the ratio $k$ so that the sum of the series $\sum_{i=0}^{\infty} l_{i}$ is equal to the circumference of the outermost circle.

score 56 · Answer 6 · 2016-01-05 16:39:14

56

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Not Deducing a Closed Form for Recurrence Relation Correctly

Published on 05 Jan 2016 - 16:39

score 234 · Answer 7 · 2026-03-26 17:30:37

234

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Pythagorean Theorem via Geometric Progression

Published on 26 Mar 2026 - 17:30

score 885 · Answer 8 · 2016-01-08 15:10:23

885

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How to express this series as a geometric series

Published on 08 Jan 2016 - 15:10

score 51 · Answer 9 · 2016-01-09 14:32:43

51

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What is the real answer for this geometric series?

Published on 09 Jan 2016 - 14:32

score 59 · Answer 10 · 2016-01-18 00:37:27

59

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Factoring to find Power Series and Radius of Convergence

Published on 18 Jan 2016 - 0:37

score 248 · Answer 11 · 2016-01-24 01:50:58

248

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Problems using D'alemberts Ratio test for convergence or divergence

Published on 24 Jan 2016 - 1:50

score 13.2k · Answer 12 · 2016-01-31 16:52:52

13.2k

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Non-infinite geometric sum; does not start at 0 or 1

Published on 31 Jan 2016 - 16:52

score 84 · Answer 13 · 2016-02-02 00:21:36

84

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Where does the group $\mathbb Z/(a)\oplus \mathbb Z/(a^2)\oplus \cdots $ arise?

Published on 02 Feb 2016 - 0:21

score 75 · Answer 14 · 2016-02-03 08:41:47

75

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Let $n$ be positive and $a > 1$. Show that $\gcd(\frac{a^n - 1}{a-1}, a-1) = \gcd(a-1, n)$

Published on 03 Feb 2016 - 8:41

score 108 · Answer 15 · 2016-02-04 07:00:17

108

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How did $-(2^{k-1})-(2^{k-2}) -\dotsb-(2^0)$ become $-2^k+1$?

Published on 04 Feb 2016 - 7:00

List Question

Write $\frac {1}{1+z^2}$ as a power series centered at $z_0=1$

Cauchy Product of two simple geometric series

Area of circles inside an equilateral triangle compared to the area of the triangle itself.

How to show that partial sums of an infinite series can be written in a different form

Determine the ratio $k$ so that the sum of the series $\sum_{i=0}^{\infty} l_{i}$ is equal to the circumference of the outermost circle.

Not Deducing a Closed Form for Recurrence Relation Correctly

Pythagorean Theorem via Geometric Progression

How to express this series as a geometric series

What is the real answer for this geometric series?

Factoring to find Power Series and Radius of Convergence

Problems using D'alemberts Ratio test for convergence or divergence

Non-infinite geometric sum; does not start at 0 or 1

Where does the group $\mathbb Z/(a)\oplus \mathbb Z/(a^2)\oplus \cdots $ arise?

Let $n$ be positive and $a > 1$. Show that $\gcd(\frac{a^n - 1}{a-1}, a-1) = \gcd(a-1, n)$

How did $-(2^{k-1})-(2^{k-2}) -\dotsb-(2^0)$ become $-2^k+1$?

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