Question

Evaluate Improper Integral: $f(b) = \int_{-\infty}^{\infty}{\exp{-b \left(\frac{1}{x^2} + \frac{1}{|x|}\right)}^{-1}}$

score 96 · Answer 1 · 2026-04-17 06:19:16

96

Views

Evaluate Improper Integral: $f(b) = \int_{-\infty}^{\infty}{\exp{-b \left(\frac{1}{x^2} + \frac{1}{|x|}\right)}^{-1}}$

Published on 17 Apr 2026 - 6:19

score 621 · Answer 2 · 2026-04-14 02:04:37

621

Views

Solving integral using Beta function

Published on 14 Apr 2026 - 2:04

score 107 · Answer 3 · 2026-04-13 05:00:26

107

Views

Evaluating an integral by setting it up as a differential equation

Published on 13 Apr 2026 - 5:00

score 810 · Answer 4 · 2026-04-17 09:01:23

810

Views

Determine whether the integral converges or diverges $\int_{1}^{\infty} \frac{\log x +\sin x}{\sqrt{x}} dx$

Published on 17 Apr 2026 - 9:01

score 2.2k · Answer 5 · 2026-04-16 23:28:47

2.2k

Views

Find all the values of $p$ for which the integral converges $\int_0^{\pi/2} \frac{\sin x}{x^p} dx$

Published on 16 Apr 2026 - 23:28

score 1.7k · Answer 6 · 2026-04-13 16:14:43

1.7k

Views

Given a continuous function which it's improper integral converges, prove/disprove $\lim_{x\to \infty}f(x)=0$

Published on 13 Apr 2026 - 16:14

score 150 · Answer 7 · 2026-04-15 13:29:08

150

Views

Bounding $\int_0^{\infty} x^p e^{-x} dx$ to find the values of p for integral convergence.

Published on 15 Apr 2026 - 13:29

score 113 · Answer 8 · 2026-04-09 09:31:58

113

Views

This integral is divergent - but why?

Published on 09 Apr 2026 - 9:31

score 132 · Answer 9 · 2026-04-16 14:19:43

If $f:[a,\infty)\to\mathbb{R}$ is monotonically decreasing, and $\int_{1}^{\infty}f(x)dx$ is convergent, then $\underset {x\to\infty} \lim f(x)=0$.

score 245 · Answer 10 · 2026-04-17 00:31:02

245

Views

does the integral $\int _{1}^{\infty }\!{\frac {\sin \left( \cos \left( x \right) +\sin \left( x\sqrt {3} \right) \right) }{x}}{dx}$ converges?

Published on 17 Apr 2026 - 0:31

score 5k · Answer 11 · 2026-04-14 12:40:03

5k

Views

Derivative of Heaviside step Function

Published on 14 Apr 2026 - 12:40

score 7.1k · Answer 12 · 2026-04-15 15:25:33

7.1k

Views

Does the Improper integral $\int_0^1 \frac{1}{\ln x}$ converge or diverge and how do you show it?

Published on 15 Apr 2026 - 15:25

score 447 · Answer 13 · 2026-04-13 14:34:22

447

Views

Prob. 9, Chap. 6, in Baby Rudin: Which one of these two improper integrals converges absolutely and which one does not?

Published on 13 Apr 2026 - 14:34

score 56 · Answer 14 · 2026-04-10 01:06:40

56

Views

Cannot Show Bound of Integral Involving Strange Integration Region

Published on 10 Apr 2026 - 1:06

score 77 · Answer 15 · 2026-04-11 22:00:16

77

Views

Conditions to the existence of a limit to a sequence of improper Riemann integrals

Published on 11 Apr 2026 - 22:00

List Question

Evaluate Improper Integral: $f(b) = \int_{-\infty}^{\infty}{\exp{-b \left(\frac{1}{x^2} + \frac{1}{|x|}\right)}^{-1}}$

Solving integral using Beta function

Evaluating an integral by setting it up as a differential equation

Determine whether the integral converges or diverges $\int_{1}^{\infty} \frac{\log x +\sin x}{\sqrt{x}} dx$

Find all the values of $p$ for which the integral converges $\int_0^{\pi/2} \frac{\sin x}{x^p} dx$

Given a continuous function which it's improper integral converges, prove/disprove $\lim_{x\to \infty}f(x)=0$

Bounding $\int_0^{\infty} x^p e^{-x} dx$ to find the values of p for integral convergence.

This integral is divergent - but why?

If $f:[a,\infty)\to\mathbb{R}$ is monotonically decreasing, and $\int_{1}^{\infty}f(x)dx$ is convergent, then $\underset {x\to\infty} \lim f(x)=0$.

does the integral $\int _{1}^{\infty }\!{\frac {\sin \left( \cos \left( x \right) +\sin \left( x\sqrt {3} \right) \right) }{x}}{dx}$ converges?

Derivative of Heaviside step Function

Does the Improper integral $\int_0^1 \frac{1}{\ln x}$ converge or diverge and how do you show it?

Prob. 9, Chap. 6, in Baby Rudin: Which one of these two improper integrals converges absolutely and which one does not?

Cannot Show Bound of Integral Involving Strange Integration Region

Conditions to the existence of a limit to a sequence of improper Riemann integrals

Trending Questions

Popular # Hahtags

Popular Questions