List questions from induction

Published on 16 Apr 2026 - 16:01

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Induction proof that $1^3+2^3+...+n^3=\frac{n^2(n+1)^2}4$

Published on 16 Apr 2026 - 18:28

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Induction proof, greater than

Published on 11 Apr 2026 - 18:52

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Fibonacci Numbers, show $F_n \ge 2^{n/2}$ for $n \ge 6$.

Published on 17 Apr 2026 - 13:52

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Prove that $n < 2^n$ for all n holds N.

Published on 14 Apr 2026 - 12:02

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Prove that $n(n-1)<3^n$ for all $n≥2$ By induction

Published on 15 Apr 2026 - 4:43

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A reccurent sequence

Published on 25 Apr 2026 - 23:03

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proving my induction in game theory doubt

Published on 12 Apr 2026 - 1:51

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Can someone make this question clear to me and give me a hint?

Published on 11 Apr 2026 - 16:21

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Trying to show a probability equation by induction

Published on 12 Apr 2026 - 18:47

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Induction divisibility proof

Published on 14 Apr 2026 - 2:21

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Prove by induction that every complete $k$-ary tree of depth $n$ has $(k^{n+1}–1)/(k-1)$ nodes for all integers $n\ge 0$, where $k\ge 2$.

Published on 15 Apr 2026 - 2:33

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Lucas Number Sequence

Published on 14 Apr 2026 - 19:43

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Proof by induction $n^2-2n-1>0$ for $n \ge 3$

Published on 16 Apr 2026 - 14:20

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Proof by Induction: $2(\sqrt{n+1} - \sqrt{n}) < \frac{1}{\sqrt{n}} < 2(\sqrt{n}-\sqrt{n-1})$

Published on 17 Apr 2026 - 5:21

List Question

Prove that $4^n > n^4$by induction for $n\ge 5$

Induction proof that $1^3+2^3+...+n^3=\frac{n^2(n+1)^2}4$

Induction proof, greater than

Fibonacci Numbers, show $F_n \ge 2^{n/2}$ for $n \ge 6$.

Prove that $n < 2^n$ for all n holds N.

Prove that $n(n-1)<3^n$ for all $n≥2$ By induction

A reccurent sequence

proving my induction in game theory doubt

Can someone make this question clear to me and give me a hint?

Trying to show a probability equation by induction

Induction divisibility proof

Prove by induction that every complete $k$-ary tree of depth $n$ has $(k^{n+1}–1)/(k-1)$ nodes for all integers $n\ge 0$, where $k\ge 2$.

Lucas Number Sequence

Proof by induction $n^2-2n-1>0$ for $n \ge 3$

Proof by Induction: $2(\sqrt{n+1} - \sqrt{n}) < \frac{1}{\sqrt{n}} < 2(\sqrt{n}-\sqrt{n-1})$

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