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Question about the structure of the proof in how the well-ordering implies induction

score 119 · Answer 1 · 2026-04-11 00:03:26

119

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Question about the structure of the proof in how the well-ordering implies induction

Published on 11 Apr 2026 - 0:03

score 428 · Answer 2 · 2026-04-16 09:59:19

428

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The digital root of factorials from 6! to infinity! is always 9.

Published on 16 Apr 2026 - 9:59

score 1.5k · Answer 3 · 2026-04-12 21:15:55

1.5k

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Induction: $\sum_{k=1}^{2n} (-1)^k k = n$

Published on 12 Apr 2026 - 21:15

score 83 · Answer 4 · 2026-04-15 18:09:06

83

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Use Proof of Induction to prove $\sum_{k=1}^{2n} (-1)^k k = n$

Published on 15 Apr 2026 - 18:09

score 105 · Answer 5 · 2026-04-15 10:34:37

105

Views

Let $y$ be real, $n$ is natural, and $\varepsilon>0$. For some $\delta>0$, if $u$ is real and $|u-y|<\delta$, then $|u^{n}-y^{n}|<\varepsilon$

Published on 15 Apr 2026 - 10:34

score 90 · Answer 6 · 2026-04-14 06:27:58

90

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Proof By Induction for arbitrary integers

Published on 14 Apr 2026 - 6:27

score 81 · Answer 7 · 2026-04-09 14:22:41

81

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Proof by Induction for Natural Numbers

Published on 09 Apr 2026 - 14:22

score 87 · Answer 8 · 2026-04-09 03:38:16

87

Views

Induction proofing of a sequence

Published on 09 Apr 2026 - 3:38

score 82 · Answer 9 · 2026-04-11 02:37:45

82

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inequality of two functions

Published on 11 Apr 2026 - 2:37

score 50 · Answer 10 · 2026-04-12 12:17:14

50

Views

How to generalize induction from this definition?

Published on 12 Apr 2026 - 12:17

score 180 · Answer 11 · 2026-04-15 19:30:18

180

Views

Double Induction of $x^n < (n^n)(2^x)$

Published on 15 Apr 2026 - 19:30

score 40 · Answer 12 · 2026-04-11 09:40:33

40

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Formalized attempt of proof that well ordered-ness ( of subsets of $\mathbb{Z}$ that are bounded below) implies induction seems to have issue?

Published on 11 Apr 2026 - 9:40

score 85 · Answer 13 · 2026-04-12 20:41:49

85

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Determining a rule for the remainder when $3^n$ is divided by $13$

Published on 12 Apr 2026 - 20:41

score 80 · Answer 14 · 2026-04-14 09:50:49

80

Views

Why does the conclusion of induction proofs hold even when the base case is greater than $1$?

Published on 14 Apr 2026 - 9:50

score 192 · Answer 15 · 2026-04-17 06:14:46

192

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Prove that $1^2 - 2^2 + 3^2 - 4^2 + \cdots + (-1)^{n-1}n^2 = \frac12(-1)^{n-1} n (n + 1)$, where $n $ is a positive integer

Published on 17 Apr 2026 - 6:14

List Question

Question about the structure of the proof in how the well-ordering implies induction

The digital root of factorials from 6! to infinity! is always 9.

Induction: $\sum_{k=1}^{2n} (-1)^k k = n$

Use Proof of Induction to prove $\sum_{k=1}^{2n} (-1)^k k = n$

Let $y$ be real, $n$ is natural, and $\varepsilon>0$. For some $\delta>0$, if $u$ is real and $|u-y|<\delta$, then $|u^{n}-y^{n}|<\varepsilon$

Proof By Induction for arbitrary integers

Proof by Induction for Natural Numbers

Induction proofing of a sequence

inequality of two functions

How to generalize induction from this definition?

Double Induction of $x^n < (n^n)(2^x)$

Formalized attempt of proof that well ordered-ness ( of subsets of $\mathbb{Z}$ that are bounded below) implies induction seems to have issue?

Determining a rule for the remainder when $3^n$ is divided by $13$

Why does the conclusion of induction proofs hold even when the base case is greater than $1$?

Prove that $1^2 - 2^2 + 3^2 - 4^2 + \cdots + (-1)^{n-1}n^2 = \frac12(-1)^{n-1} n (n + 1)$, where $n $ is a positive integer

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