Show that for every $x$ there exists a $n \in \mathbb{N}$ so that $f(x-(\frac{1}{2})^{n} \nabla f(x)) \leq f(x)-(\frac{1}{2})^{n+1} ||\nabla f(x)||^2$

score 65 · Answer 14 · 2026-04-16 20:32:16

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Is this inequality true? $u^2+v^2+s^2+t^2\geq (u+v)(s+t)$

Published on 16 Apr 2026 - 20:32

score 962 · Answer 15 · 2026-04-11 18:58:32

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Proving subadditivity of max norm for matrices

Published on 11 Apr 2026 - 18:58

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Show that for every $x$ there exists a $n \in \mathbb{N}$ so that $f(x-(\frac{1}{2})^{n} \nabla f(x)) \leq f(x)-(\frac{1}{2})^{n+1} ||\nabla f(x)||^2$

Is this inequality true? $u^2+v^2+s^2+t^2\geq (u+v)(s+t)$

Proving subadditivity of max norm for matrices

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