Question

prove $(t+1)^x+(t-1)^x-2t^x>0$ for any e: $x$ and any $t>1$

score 55 · Answer 1 · 2018-07-05 10:00:00

55

Views

prove $(t+1)^x+(t-1)^x-2t^x>0$ for any e: $x$ and any $t>1$

Published on 05 Jul 2018 - 10:00

score 63 · Answer 2 · 2018-07-05 16:25:46

63

Views

Prove that $b^3 \log(b) - a^3\log(a) \le 4e^2(b-a)$

Published on 05 Jul 2018 - 16:25

score 87 · Answer 3 · 2026-03-25 10:53:39

87

Views

Evaluating $y(1)$ in the initial value problem $\dot y = ty + \sin y , y(0)=10^{-2}$

Published on 25 Mar 2026 - 10:53

score 95 · Answer 4 · 2026-03-25 09:33:24

95

Views

Bounded completely monotone function has bounded derivative

Published on 25 Mar 2026 - 9:33

score 62 · Answer 5 · 2026-04-01 05:01:34

62

Views

Solving $2\log(n!) - n\log n \le 2n\log n$

Published on 01 Apr 2026 - 5:01

score 112 · Answer 6 · 2018-07-05 23:10:03

Show that $(\prod_{i=1}^{n} (a_i+b_i))^{\frac{1}{n}} \geq (\prod_{i=1}^{n} {a_i})^{\frac{1}{n}}+(\prod_{i=1}^{n} {b_i})^{\frac{1}{n}}$

score 150 · Answer 7 · 2026-03-26 16:14:04

150

Views

Range of $(a_{1}-a_{2})^2+(a_{2}-a_{3})^2+(a_{3}-a_{4})^2+(a_{4}-a_{1})^2$ is

Published on 26 Mar 2026 - 16:14

score 443 · Answer 8 · 2026-03-30 05:26:45

443

Views

Let $P(x)\in \mathbb{R}[x]$ be of degree $n$ and for any $x \in \left(0,1\right]$, we have $x\cdot P^2(x) \le 1$. Calculate $\max P(0)$.

Published on 30 Mar 2026 - 5:26

score 451 · Answer 9 · 2026-03-24 23:46:11

451

Views

Graphing Inequality: 5x+10y >0 Saw the graph answer but I can't understand it.

Published on 24 Mar 2026 - 23:46

score 47 · Answer 10 · 2018-07-06 22:31:40

47

Views

Deriving bounds on a parameter for the following determinant inequality

Published on 06 Jul 2018 - 22:31

score 99 · Answer 11 · 2026-03-25 01:16:26

99

Views

Trig function bounded on interval (without calculus), prove that $x^{3/2}\sin x + \sqrt{9-x^3}\cos x \leq 3$.

Published on 25 Mar 2026 - 1:16

score 4.2k · Answer 12 · 2026-04-03 01:46:35

4.2k

Views

prove that the polynomial $x^8 -x^5 +x^2 -x +1$ is positive for all real values of x

Published on 03 Apr 2026 - 1:46

score 63 · Answer 13 · 2018-07-07 13:37:48

63

Views

What is the solution to this inequality: $|2x+5| <\frac{1}{2}$

Published on 07 Jul 2018 - 13:37

score 605 · Answer 14 · 2018-07-07 14:18:01

605

Views

What is the solution to this inequality: $| 2x-3| > - | x+3|?$

Published on 07 Jul 2018 - 14:18

score 147 · Answer 15 · 2018-07-07 21:11:32

147

Views

Show that $\sum_{i=1}^{n} \frac {a_i}{1+a-a_i} + \prod_{i=1}^{n} {(1-a_i)} \leq 1$

Published on 07 Jul 2018 - 21:11

List Question

prove $(t+1)^x+(t-1)^x-2t^x>0$ for any e: $x$ and any $t>1$

Prove that $b^3 \log(b) - a^3\log(a) \le 4e^2(b-a)$

Evaluating $y(1)$ in the initial value problem $\dot y = ty + \sin y , y(0)=10^{-2}$

Bounded completely monotone function has bounded derivative

Solving $2\log(n!) - n\log n \le 2n\log n$

Show that $(\prod_{i=1}^{n} (a_i+b_i))^{\frac{1}{n}} \geq (\prod_{i=1}^{n} {a_i})^{\frac{1}{n}}+(\prod_{i=1}^{n} {b_i})^{\frac{1}{n}}$

Range of $(a_{1}-a_{2})^2+(a_{2}-a_{3})^2+(a_{3}-a_{4})^2+(a_{4}-a_{1})^2$ is

Let $P(x)\in \mathbb{R}[x]$ be of degree $n$ and for any $x \in \left(0,1\right]$, we have $x\cdot P^2(x) \le 1$. Calculate $\max P(0)$.

Graphing Inequality: 5x+10y >0 Saw the graph answer but I can't understand it.

Deriving bounds on a parameter for the following determinant inequality

Trig function bounded on interval (without calculus), prove that $x^{3/2}\sin x + \sqrt{9-x^3}\cos x \leq 3$.

prove that the polynomial $x^8 -x^5 +x^2 -x +1$ is positive for all real values of x

What is the solution to this inequality: $|2x+5| <\frac{1}{2}$

What is the solution to this inequality: $| 2x-3| > - | x+3|?$

Show that $\sum_{i=1}^{n} \frac {a_i}{1+a-a_i} + \prod_{i=1}^{n} {(1-a_i)} \leq 1$

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