Question

Orthogonality of limits in arbitrary inner product space

score 163 · Answer 1 · 2026-04-15 18:43:14

163

Views

Orthogonality of limits in arbitrary inner product space

Published on 15 Apr 2026 - 18:43

score 3.3k · Answer 2 · 2026-04-14 21:45:12

3.3k

Views

Inverse of Inner Product

Published on 14 Apr 2026 - 21:45

score 82 · Answer 3 · 2026-04-17 09:29:10

82

Views

Is my proof that b(x,y) = <Bx,y>, using bilinearity, correct?

Published on 17 Apr 2026 - 9:29

score 164 · Answer 4 · 2015-11-17 01:28:25

164

Views

Polarization identity $2(a,b)(c,d)=(ac,bd)+(ad,bc)$

Published on 17 Nov 2015 - 1:28

score 40 · Answer 5 · 2026-04-11 08:57:06

40

Views

The function is a norm on $X$

Published on 11 Apr 2026 - 8:57

score 409 · Answer 6 · 2026-04-11 00:09:20

409

Views

Properties of adjoint matrix in a finite dimensional inner product space

Published on 11 Apr 2026 - 0:09

score 267 · Answer 7 · 2026-04-16 04:59:52

267

Views

Let $U$ be a unitary matrix, show that $r(x,y) := x^*Uy$ is an inner product.

Published on 16 Apr 2026 - 4:59

score 65 · Answer 8 · 2026-04-16 15:38:26

Show that there is an innerproduct on $X/Y$ such that $\langle\langle{x+Y,x+Y}\rangle\rangle={\lvert\lvert\lvert{x+Y}\rvert\rvert\rvert}^2$

score 308 · Answer 9 · 2026-04-11 02:26:00

308

Views

How to normalize an eigenvector when it has $\sqrt{i}$ as an entry?

Published on 11 Apr 2026 - 2:26

score 150 · Answer 10 · 2026-04-10 09:46:20

150

Views

Cauchy schwarz inequality for inner product proof understanding

Published on 10 Apr 2026 - 9:46

score 72 · Answer 11 · 2026-04-17 03:14:18

72

Views

Why is $\langle\alpha x+y, \alpha x+y\rangle = |\alpha|^2\|x\|^2 + (\alpha\langle x, y\rangle + \bar{\alpha}\langle y, x\rangle) + \|y\|^2.$

Published on 17 Apr 2026 - 3:14

score 810 · Answer 12 · 2026-04-17 11:36:57

810

Views

Is every hyperplane in $\mathbb{R}^n$ determined by a unique normal vector?

Published on 17 Apr 2026 - 11:36

score 293 · Answer 13 · 2026-04-16 08:18:00

293

Views

Orthonormal basis for a complex vector space with countable vector space

Published on 16 Apr 2026 - 8:18

score 1.1k · Answer 14 · 2026-04-13 06:44:29

1.1k

Views

Let $V$ be a complex inner product space and $T$ a self-adjoint linear operator on $V$. Show that $I + iT$ is non-singular.

Published on 13 Apr 2026 - 6:44

score 178 · Answer 15 · 2026-04-13 16:25:19

178

Views

Defining a Euclidean Structure on a real vector space.

Published on 13 Apr 2026 - 16:25

List Question

Orthogonality of limits in arbitrary inner product space

Inverse of Inner Product

Is my proof that b(x,y) = <Bx,y>, using bilinearity, correct?

Polarization identity $2(a,b)(c,d)=(ac,bd)+(ad,bc)$

The function is a norm on $X$

Properties of adjoint matrix in a finite dimensional inner product space

Let $U$ be a unitary matrix, show that $r(x,y) := x^*Uy$ is an inner product.

Show that there is an innerproduct on $X/Y$ such that $\langle\langle{x+Y,x+Y}\rangle\rangle={\lvert\lvert\lvert{x+Y}\rvert\rvert\rvert}^2$

How to normalize an eigenvector when it has $\sqrt{i}$ as an entry?

Cauchy schwarz inequality for inner product proof understanding

Why is $\langle\alpha x+y, \alpha x+y\rangle = |\alpha|^2\|x\|^2 + (\alpha\langle x, y\rangle + \bar{\alpha}\langle y, x\rangle) + \|y\|^2.$

Is every hyperplane in $\mathbb{R}^n$ determined by a unique normal vector?

Orthonormal basis for a complex vector space with countable vector space

Let $V$ be a complex inner product space and $T$ a self-adjoint linear operator on $V$. Show that $I + iT$ is non-singular.

Defining a Euclidean Structure on a real vector space.

Trending Questions

Popular # Hahtags

Popular Questions