Question

Are unique prime ideal factorization domains locally noetherian?

score 80 · Answer 1 · 2019-01-05 11:47:54

80

Views

Are unique prime ideal factorization domains locally noetherian?

Published on 05 Jan 2019 - 11:47

score 638 · Answer 2 · 2019-01-08 02:51:38

638

Views

Why is it natural to define a prime as $p|ab$ implies $p|a$ or $p|b$?

Published on 08 Jan 2019 - 2:51

score 242 · Answer 3 · 2019-01-10 09:05:10

242

Views

Integral Domain, PID and gcd

Published on 10 Jan 2019 - 9:05

score 767 · Answer 4 · 2019-01-15 09:13:23

767

Views

If A is a finite integral domain and is a cyclic group with addition alone, then order of A is prime

Published on 15 Jan 2019 - 9:13

score 46 · Answer 5 · 2019-01-15 15:16:49

46

Views

If $A$ and $B$ are integral domains and $A \subseteq B$ then $A$ has characteristic $p$ iff $B$ has characteristic $p$

Published on 15 Jan 2019 - 15:16

score 26 · Answer 6 · 2019-01-15 23:38:19

26

Views

Trouble understanding proof regarding elements of an integral domain which are not product of irreducible elements.

Published on 15 Jan 2019 - 23:38

score 160 · Answer 7 · 2019-01-24 16:44:51

160

Views

ideal extension in polynomial ring over quotient field

Published on 24 Jan 2019 - 16:44

score 251 · Answer 8 · 2019-01-25 21:58:57

251

Views

On ideal quotient of intersection of fractional ideals

Published on 25 Jan 2019 - 21:58

score 66 · Answer 9 · 2019-02-04 18:37:19

66

Views

Is $\mathbb{Z}[X]/(I+J)$ integral domain

Published on 04 Feb 2019 - 18:37

score 83 · Answer 10 · 2019-02-05 17:12:21

83

Views

If $\sigma^{*}\left(p\left(x\right)\right)$ is irreducible in $S\left[x\right]$, then $p\left(x\right)$ is irreducible in $R\left[x\right]$.

Published on 05 Feb 2019 - 17:12

score 339 · Answer 11 · 2019-02-06 03:22:42

339

Views

The ideal generated by an irreducible element contains a prime ideal implies that the element is prime in a non-UFD?

Published on 06 Feb 2019 - 3:22

score 174 · Answer 12 · 2019-02-08 19:31:39

174

Views

Lang's Algebra: definition of $F[\alpha]$ and why it's an integral domain?

Published on 08 Feb 2019 - 19:31

score 24 · Answer 13 · 2019-02-12 23:03:17

24

Views

$R$ UFD and integral domain $\Rightarrow$ every $a\neq 0 \in R\setminus R^\times$ is a product of prime elements

Published on 12 Feb 2019 - 23:03

score 106 · Answer 14 · 2019-02-13 21:46:56

106

Views

Integral domain which contains a copy of its fraction field

Published on 13 Feb 2019 - 21:46

score 13 · Answer 15 · 2019-02-20 06:04:12

13

Views

How to find the irreducible factors in this domain?

Published on 20 Feb 2019 - 6:04

List Question

Are unique prime ideal factorization domains locally noetherian?

Why is it natural to define a prime as $p|ab$ implies $p|a$ or $p|b$?

Integral Domain, PID and gcd

If A is a finite integral domain and is a cyclic group with addition alone, then order of A is prime

If $A$ and $B$ are integral domains and $A \subseteq B$ then $A$ has characteristic $p$ iff $B$ has characteristic $p$

Trouble understanding proof regarding elements of an integral domain which are not product of irreducible elements.

ideal extension in polynomial ring over quotient field

On ideal quotient of intersection of fractional ideals

Is $\mathbb{Z}[X]/(I+J)$ integral domain

If $\sigma^{*}\left(p\left(x\right)\right)$ is irreducible in $S\left[x\right]$, then $p\left(x\right)$ is irreducible in $R\left[x\right]$.

The ideal generated by an irreducible element contains a prime ideal implies that the element is prime in a non-UFD?

Lang's Algebra: definition of $F[\alpha]$ and why it's an integral domain?

$R$ UFD and integral domain $\Rightarrow$ every $a\neq 0 \in R\setminus R^\times$ is a product of prime elements

Integral domain which contains a copy of its fraction field

How to find the irreducible factors in this domain?

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