Question

Is my estimation of the equality given below true?

score 18 · Answer 1 · 2019-10-05 10:08:12

18

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Is my estimation of the equality given below true?

Published on 05 Oct 2019 - 10:08

score 62 · Answer 2 · 2019-10-05 14:18:03

62

Views

Lower bound $\int_0^\infty e^{-t-\frac{t^2}{2\sigma^2}}dt$ by $1-\frac{1}{\sigma^2}$

Published on 05 Oct 2019 - 14:18

score 46 · Answer 3 · 2019-10-07 02:58:21

46

Views

Conjectured decreasing of sequence of integrals of products of Fourier transformations

Published on 07 Oct 2019 - 2:58

score 2.2k · Answer 4 · 2019-10-16 15:41:26

2.2k

Views

Does an integral preserve strict inequality?

Published on 16 Oct 2019 - 15:41

score 269 · Answer 5 · 2019-10-19 17:18:04

269

Views

Is it true that $\phi(\mu)=\mu F(\mu)^2-\int_{\mu}^{\overline{v}}F(v)[1-F(v)]dv\geq 0$?

Published on 19 Oct 2019 - 17:18

score 126 · Answer 6 · 2019-10-20 04:50:19

126

Views

For cubic $P(x)$ with a root in $[0,1]$, find the smallest $C$ such that $\int_0^1 |P(x)|dx\leq C\max_{x\in[0,1]}|P(x)|$

Published on 20 Oct 2019 - 4:50

score 83 · Answer 7 · 2019-10-21 18:46:31

83

Views

Positivity condition from integral

Published on 21 Oct 2019 - 18:46

score 87 · Answer 8 · 2026-03-25 13:52:56

87

Views

Proof of a functional inequality

Published on 25 Mar 2026 - 13:52

score 46 · Answer 9 · 2019-10-27 08:34:14

46

Views

Possible geometric interpretation of an integral inequality

Published on 27 Oct 2019 - 8:34

score 332 · Answer 10 · 2019-10-30 19:50:41

332

Views

Prove that $\int\limits_0^1 \bigg | \frac{f''(x)}{f(x)} \bigg| dx \ge \frac{4(M-1)}{M}$

Published on 30 Oct 2019 - 19:50

score 27 · Answer 11 · 2019-11-01 04:00:38

27

Views

Gromov's claim on inequality of integrals.

Published on 01 Nov 2019 - 4:00

score 112 · Answer 12 · 2019-11-06 03:25:12

112

Views

$\int \bigg||f|^p-|g|^p\bigg|d\mu\leq \int \big|f-g\big|^pd\mu$ , for $ 0<p<1$

Published on 06 Nov 2019 - 3:25

score 164 · Answer 13 · 2019-11-06 18:56:45

164

Views

Prove that $\int\limits_0^1 f(x) dx \le - \bigg |f\left(\frac{1}{2}\right)\bigg | + \frac{5}{24} \sup\limits_{x\in [0,1]}|f''(x)|$

Published on 06 Nov 2019 - 18:56

score 165 · Answer 14 · 2026-03-22 08:17:50

165

Views

Examples of Besov functions of power-logarithmic type $|x|^{\alpha} |\log |x||^{\beta}$

Published on 22 Mar 2026 - 8:17

score 118 · Answer 15 · 2019-11-12 16:29:32

118

Views

True or false? An expectation inequality

Published on 12 Nov 2019 - 16:29

List Question

Is my estimation of the equality given below true?

Lower bound $\int_0^\infty e^{-t-\frac{t^2}{2\sigma^2}}dt$ by $1-\frac{1}{\sigma^2}$

Conjectured decreasing of sequence of integrals of products of Fourier transformations

Does an integral preserve strict inequality?

Is it true that $\phi(\mu)=\mu F(\mu)^2-\int_{\mu}^{\overline{v}}F(v)[1-F(v)]dv\geq 0$?

For cubic $P(x)$ with a root in $[0,1]$, find the smallest $C$ such that $\int_0^1 |P(x)|dx\leq C\max_{x\in[0,1]}|P(x)|$

Positivity condition from integral

Proof of a functional inequality

Possible geometric interpretation of an integral inequality

Prove that $\int\limits_0^1 \bigg | \frac{f''(x)}{f(x)} \bigg| dx \ge \frac{4(M-1)}{M}$

Gromov's claim on inequality of integrals.

$\int \bigg||f|^p-|g|^p\bigg|d\mu\leq \int \big|f-g\big|^pd\mu$ , for $ 0<p<1$

Prove that $\int\limits_0^1 f(x) dx \le - \bigg |f\left(\frac{1}{2}\right)\bigg | + \frac{5}{24} \sup\limits_{x\in [0,1]}|f''(x)|$

Examples of Besov functions of power-logarithmic type $|x|^{\alpha} |\log |x||^{\beta}$

True or false? An expectation inequality

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