Question

Is my estimation of the equality given below true?

score 21 · Answer 1 · 2026-04-14 06:39:19

21

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Is my estimation of the equality given below true?

Published on 14 Apr 2026 - 6:39

score 64 · Answer 2 · 2026-05-05 16:06:22

64

Views

Lower bound $\int_0^\infty e^{-t-\frac{t^2}{2\sigma^2}}dt$ by $1-\frac{1}{\sigma^2}$

Published on 05 May 2026 - 16:06

score 49 · Answer 3 · 2026-04-12 13:48:21

49

Views

Conjectured decreasing of sequence of integrals of products of Fourier transformations

Published on 12 Apr 2026 - 13:48

score 2.2k · Answer 4 · 2026-04-08 23:49:20

2.2k

Views

Does an integral preserve strict inequality?

Published on 08 Apr 2026 - 23:49

score 272 · Answer 5 · 2026-04-15 18:08:52

272

Views

Is it true that $\phi(\mu)=\mu F(\mu)^2-\int_{\mu}^{\overline{v}}F(v)[1-F(v)]dv\geq 0$?

Published on 15 Apr 2026 - 18:08

score 129 · Answer 6 · 2026-04-17 14:49:29

129

Views

For cubic $P(x)$ with a root in $[0,1]$, find the smallest $C$ such that $\int_0^1 |P(x)|dx\leq C\max_{x\in[0,1]}|P(x)|$

Published on 17 Apr 2026 - 14:49

score 86 · Answer 7 · 2026-04-12 18:37:49

86

Views

Positivity condition from integral

Published on 12 Apr 2026 - 18:37

score 88 · Answer 8 · 2026-05-10 20:50:58

88

Views

Proof of a functional inequality

Published on 10 May 2026 - 20:50

score 49 · Answer 9 · 2026-04-09 10:44:16

49

Views

Possible geometric interpretation of an integral inequality

Published on 09 Apr 2026 - 10:44

score 335 · Answer 10 · 2026-04-15 15:10:42

335

Views

Prove that $\int\limits_0^1 \bigg | \frac{f''(x)}{f(x)} \bigg| dx \ge \frac{4(M-1)}{M}$

Published on 15 Apr 2026 - 15:10

score 30 · Answer 11 · 2026-04-14 19:47:15

30

Views

Gromov's claim on inequality of integrals.

Published on 14 Apr 2026 - 19:47

score 115 · Answer 12 · 2026-04-17 00:10:09

115

Views

$\int \bigg||f|^p-|g|^p\bigg|d\mu\leq \int \big|f-g\big|^pd\mu$ , for $ 0<p<1$

Published on 17 Apr 2026 - 0:10

score 167 · Answer 13 · 2026-04-16 19:59:49

167

Views

Prove that $\int\limits_0^1 f(x) dx \le - \bigg |f\left(\frac{1}{2}\right)\bigg | + \frac{5}{24} \sup\limits_{x\in [0,1]}|f''(x)|$

Published on 16 Apr 2026 - 19:59

score 171 · Answer 14 · 2026-05-13 13:27:53

171

Views

Examples of Besov functions of power-logarithmic type $|x|^{\alpha} |\log |x||^{\beta}$

Published on 13 May 2026 - 13:27

score 121 · Answer 15 · 2026-04-15 12:42:25

121

Views

True or false? An expectation inequality

Published on 15 Apr 2026 - 12:42

List Question

Is my estimation of the equality given below true?

Lower bound $\int_0^\infty e^{-t-\frac{t^2}{2\sigma^2}}dt$ by $1-\frac{1}{\sigma^2}$

Conjectured decreasing of sequence of integrals of products of Fourier transformations

Does an integral preserve strict inequality?

Is it true that $\phi(\mu)=\mu F(\mu)^2-\int_{\mu}^{\overline{v}}F(v)[1-F(v)]dv\geq 0$?

For cubic $P(x)$ with a root in $[0,1]$, find the smallest $C$ such that $\int_0^1 |P(x)|dx\leq C\max_{x\in[0,1]}|P(x)|$

Positivity condition from integral

Proof of a functional inequality

Possible geometric interpretation of an integral inequality

Prove that $\int\limits_0^1 \bigg | \frac{f''(x)}{f(x)} \bigg| dx \ge \frac{4(M-1)}{M}$

Gromov's claim on inequality of integrals.

$\int \bigg||f|^p-|g|^p\bigg|d\mu\leq \int \big|f-g\big|^pd\mu$ , for $ 0<p<1$

Prove that $\int\limits_0^1 f(x) dx \le - \bigg |f\left(\frac{1}{2}\right)\bigg | + \frac{5}{24} \sup\limits_{x\in [0,1]}|f''(x)|$

Examples of Besov functions of power-logarithmic type $|x|^{\alpha} |\log |x||^{\beta}$

True or false? An expectation inequality

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