List questions from intuition

Published on 31 Jul 2014 - 0:02

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Using De Moivre's theorem with relation to the argument of a complex number

Published on 01 Aug 2014 - 1:44

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Using De-moivres to solve the following problem:

Published on 05 Aug 2014 - 3:40

728

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Problem involving summing exponential series:

Published on 25 Mar 2026 - 10:15

536

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Trigonometric series problem: finding a second valid solution.

Published on 26 Mar 2026 - 11:24

54

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Show that $ \frac{2+\ln a }{2}\lt\frac{a-1}{\ln a} \lt \frac{1+a}{2}$ becomes $ \frac{2(a-1)}{a+1}\lt\ln a \lt -1 + \sqrt{2a-1}$

Published on 26 Mar 2026 - 11:01

33

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Understanding Inequalities.

Published on 08 Aug 2014 - 7:48

462

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Everyday life examples of hyperbolic rotations

Published on 27 Mar 2026 - 7:14

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Explaining multiplication of fractions

Published on 27 Mar 2026 - 5:56

96

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Sequential Algebraic Problem:

Published on 09 Aug 2014 - 4:21

80

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Series problem:

Published on 10 Aug 2014 - 7:23

184

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How to determine value from willingness to pay?

Published on 10 Aug 2014 - 9:45

508

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Computing of the Gamma Function

Published on 28 Mar 2026 - 2:59

93

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By plugging $p=1-q$, into the $3$ equations show that $x=y=z$

Published on 11 Aug 2014 - 9:28

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Show that $q^4+2pq^2 +p^2 = 2pq -(pq)^2 -1$ becomes $p^3+q^3+3pq-1=0$.

Published on 11 Aug 2014 - 9:52

List Question

Distinction between nowhere monotone and nowhere differentiable

Using De Moivre's theorem with relation to the argument of a complex number

Using De-moivres to solve the following problem:

Problem involving summing exponential series:

Trigonometric series problem: finding a second valid solution.

Show that $ \frac{2+\ln a }{2}\lt\frac{a-1}{\ln a} \lt \frac{1+a}{2}$ becomes $ \frac{2(a-1)}{a+1}\lt\ln a \lt -1 + \sqrt{2a-1}$

Understanding Inequalities.

Everyday life examples of hyperbolic rotations

Explaining multiplication of fractions

Sequential Algebraic Problem:

Series problem:

How to determine value from willingness to pay?

Computing of the Gamma Function

By plugging $p=1-q$, into the $3$ equations show that $x=y=z$

Show that $q^4+2pq^2 +p^2 = 2pq -(pq)^2 -1$ becomes $p^3+q^3+3pq-1=0$.

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