Question

Description of the algebra of $G$-invariant polynomials by generators and relations

score 253 · Answer 1 · 2015-12-06 01:23:45

253

Views

Description of the algebra of $G$-invariant polynomials by generators and relations

Published on 06 Dec 2015 - 1:23

score 327 · Answer 2 · 2015-12-09 22:22:59

327

Views

$\mathbb C[X_1, \ldots, X_n]$ is a free module over $\mathbb C[X_1, \ldots, X_n]^G$

Published on 09 Dec 2015 - 22:22

score 294 · Answer 3 · 2015-12-15 00:08:29

294

Views

What is a trivial linear operator?

Published on 15 Dec 2015 - 0:08

score 119 · Answer 4 · 2016-01-02 19:38:19

119

Views

Does the invariant ring determine the group?

Published on 02 Jan 2016 - 19:38

score 94 · Answer 5 · 2016-01-03 12:22:09

94

Views

Is a polynomial which is invariant in the roots of some separable polynomial also invariant in the usual sense?

Published on 03 Jan 2016 - 12:22

score 80 · Answer 6 · 2026-03-22 13:29:01

80

Views

What is known about rational points on the ideal of relations / syzygy ideal?

Published on 22 Mar 2026 - 13:29

score 962 · Answer 7 · 2016-01-05 11:59:49

962

Views

Ring of Invariants of symmetric group

Published on 05 Jan 2016 - 11:59

score 89 · Answer 8 · 2016-01-12 10:59:05

89

Views

Invariant ring for $S_5$

Published on 12 Jan 2016 - 10:59

score 64 · Answer 9 · 2016-01-13 04:55:27

64

Views

Given $\pi:X\rightarrow Y$ how to show $X$ is irreducible (resp. normal) $\Rightarrow$ $Y$ is irreducible(resp. normal)?

Published on 13 Jan 2016 - 4:55

score 247 · Answer 10 · 2016-01-16 11:22:48

247

Views

Equivalent definition of almost geometric quotient

Published on 16 Jan 2016 - 11:22

score 113 · Answer 11 · 2016-01-17 13:16:57

113

Views

Calculating the ring of invariants for the action of $\mathbb C^*$ on $\mathbb C^2\setminus \{0\}$

Published on 17 Jan 2016 - 13:16

score 90 · Answer 12 · 2016-01-20 21:55:55

90

Views

G-invariant polynomials for a concrete G

Published on 20 Jan 2016 - 21:55

score 188 · Answer 13 · 2016-01-23 13:06:11

188

Views

Is there an invariant similar to the characteristic polynomial for (0,2) and (2,0) tensors?

Published on 23 Jan 2016 - 13:06

score 405 · Answer 14 · 2016-01-23 20:53:02

405

Views

Canonical forms for tensors of type (2,1)

Published on 23 Jan 2016 - 20:53

score 105 · Answer 15 · 2016-01-27 00:45:53

105

Views

If $p_T(x)=(x-\lambda_1)^{n_1}\dots(x-\lambda_t)^{n_t}$, find $t$ operators such that $T=T_1\oplus\dots\oplus T_t$

Published on 27 Jan 2016 - 0:45

List Question

Description of the algebra of $G$-invariant polynomials by generators and relations

$\mathbb C[X_1, \ldots, X_n]$ is a free module over $\mathbb C[X_1, \ldots, X_n]^G$

What is a trivial linear operator?

Does the invariant ring determine the group?

Is a polynomial which is invariant in the roots of some separable polynomial also invariant in the usual sense?

What is known about rational points on the ideal of relations / syzygy ideal?

Ring of Invariants of symmetric group

Invariant ring for $S_5$

Given $\pi:X\rightarrow Y$ how to show $X$ is irreducible (resp. normal) $\Rightarrow$ $Y$ is irreducible(resp. normal)?

Equivalent definition of almost geometric quotient

Calculating the ring of invariants for the action of $\mathbb C^*$ on $\mathbb C^2\setminus \{0\}$

G-invariant polynomials for a concrete G

Is there an invariant similar to the characteristic polynomial for (0,2) and (2,0) tensors?

Canonical forms for tensors of type (2,1)

If $p_T(x)=(x-\lambda_1)^{n_1}\dots(x-\lambda_t)^{n_t}$, find $t$ operators such that $T=T_1\oplus\dots\oplus T_t$

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