Question

Jordan canonical form with 2 is the dimension of eigenespace,

score 113 · Answer 1 · 2019-08-18 20:40:23

113

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Jordan canonical form with 2 is the dimension of eigenespace,

Published on 18 Aug 2019 - 20:40

score 560 · Answer 2 · 2019-08-19 02:46:35

560

Views

Finding the Jordan form given nullities

Published on 19 Aug 2019 - 2:46

score 70 · Answer 3 · 2019-08-20 01:06:32

70

Views

System of equations involving complex eigenvalues

Published on 20 Aug 2019 - 1:06

score 261 · Answer 4 · 2019-08-26 18:20:14

261

Views

Find a Jordan basis for the linear operator $T$

Published on 26 Aug 2019 - 18:20

score 69 · Answer 5 · 2026-03-27 15:56:38

69

Views

Show exists a subspace $W \subseteq \mathbb{C}^{n}$ of dimension $1$ such that every Jordan basis of $ \mathbb{C}^{n}$ contains a generator of $W$

Published on 27 Mar 2026 - 15:56

score 245 · Answer 6 · 2019-09-05 12:56:48

245

Views

Understanding the proof of Jordan normal form, by matrix trick

Published on 05 Sep 2019 - 12:56

score 590 · Answer 7 · 2019-09-06 21:16:49

590

Views

Finding the Jordan canonical form when the characteristic polynomial does not split?

Published on 06 Sep 2019 - 21:16

score 2.2k · Answer 8 · 2026-03-26 09:06:33

2.2k

Views

Matrix exponential using Jordan form

Published on 26 Mar 2026 - 9:06

score 334 · Answer 9 · 2019-09-10 10:48:45

334

Views

Is this a family of similar matrices $\left(\begin{smallmatrix} 0&x\\ 0&0 \end{smallmatrix}\right)$?

Published on 10 Sep 2019 - 10:48

score 44 · Answer 10 · 2019-09-24 15:09:59

Jordan Normal Form of $A_{\pi}: \mathbb{C}^n \to \mathbb{C}^n$ given by $A_{\pi}(v) = A_{\pi}(v_1,...,v_n) = (v_{\pi(1)},...,v_{\pi(n)})$.

score 139 · Answer 11 · 2019-09-25 13:08:47

139

Views

Linear maps satisfying $T^2 = I_n$ and Jordan Form of $T(X) = AX - XA$

Published on 25 Sep 2019 - 13:08

score 101 · Answer 12 · 2026-03-26 13:30:22

101

Views

Eigenvalues of matrix exponential and its Jordan form

Published on 26 Mar 2026 - 13:30

score 4.1k · Answer 13 · 2014-03-12 14:57:39

4.1k

Views

All Possible Jordan Canonical Forms Given Characteristic Polynomial

Published on 12 Mar 2014 - 14:57

score 310 · Answer 14 · 2014-03-21 18:26:34

310

Views

Proof that Jordan form with eigenvalues of 0 is nilpotent

Published on 21 Mar 2014 - 18:26

score 914 · Answer 15 · 2026-03-27 21:57:44

914

Views

If A is an nxn matrix of complex numbers such that some power of A is identity, then i want to prove that A is diagonalizable over C

Published on 27 Mar 2026 - 21:57

List Question

Jordan canonical form with 2 is the dimension of eigenespace,

Finding the Jordan form given nullities

System of equations involving complex eigenvalues

Find a Jordan basis for the linear operator $T$

Show exists a subspace $W \subseteq \mathbb{C}^{n}$ of dimension $1$ such that every Jordan basis of $ \mathbb{C}^{n}$ contains a generator of $W$

Understanding the proof of Jordan normal form, by matrix trick

Finding the Jordan canonical form when the characteristic polynomial does not split?

Matrix exponential using Jordan form

Is this a family of similar matrices $\left(\begin{smallmatrix} 0&x\\ 0&0 \end{smallmatrix}\right)$?

Jordan Normal Form of $A_{\pi}: \mathbb{C}^n \to \mathbb{C}^n$ given by $A_{\pi}(v) = A_{\pi}(v_1,...,v_n) = (v_{\pi(1)},...,v_{\pi(n)})$.

Linear maps satisfying $T^2 = I_n$ and Jordan Form of $T(X) = AX - XA$

Eigenvalues of matrix exponential and its Jordan form

All Possible Jordan Canonical Forms Given Characteristic Polynomial

Proof that Jordan form with eigenvalues of 0 is nilpotent

If A is an nxn matrix of complex numbers such that some power of A is identity, then i want to prove that A is diagonalizable over C

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