Question

Find the principal part of the Laurent expansion of $\frac{(z^{2}-2z-3)^{2}}{\cos(\pi z)+1}$ around $z_{0}=1$

score 1.8k · Answer 1 · 2013-08-26 19:00:35

1.8k

Views

Find the principal part of the Laurent expansion of $\frac{(z^{2}-2z-3)^{2}}{\cos(\pi z)+1}$ around $z_{0}=1$

Published on 26 Aug 2013 - 19:00

score 129 · Answer 2 · 2013-08-27 11:13:12

129

Views

Find the Laurant expansion

Published on 27 Aug 2013 - 11:13

score 396 · Answer 3 · 2013-09-14 14:09:55

396

Views

Laurent Series of the function

Published on 14 Sep 2013 - 14:09

score 318 · Answer 4 · 2013-09-23 05:01:44

318

Views

Laurent expansion

Published on 23 Sep 2013 - 5:01

score 1.3k · Answer 5 · 2013-09-24 13:13:38

1.3k

Views

How to switch to a Laurent series' next convergence ring?

Published on 24 Sep 2013 - 13:13

score 251 · Answer 6 · 2013-09-30 08:42:47

251

Views

Is there a completion of Laurent series w.r.t. integration?

Published on 30 Sep 2013 - 8:42

score 4.6k · Answer 7 · 2013-09-30 11:35:17

4.6k

Views

Laurent series of a trigonometric function

Published on 30 Sep 2013 - 11:35

score 584 · Answer 8 · 2013-10-02 13:13:27

584

Views

Given a meromorphic function (via its Laurent series), how to obtain the (Taylor series of the) two holomorphic functions it is the quotient of?

Published on 02 Oct 2013 - 13:13

score 2.7k · Answer 9 · 2013-10-02 18:13:02

2.7k

Views

Show that $\frac{z}{(z-1)(z-3)} = -3\sum\limits_{n=0}^{\infty}\frac{(z-1)^n}{2^{n+2}} - \frac{1}{2(z-1)}$.

Published on 02 Oct 2013 - 18:13

score 135 · Answer 10 · 2013-10-07 05:52:28

135

Views

Trouble finding the Laurent Expansion .

Published on 07 Oct 2013 - 5:52

score 105 · Answer 11 · 2013-10-10 20:50:22

105

Views

Is it possible to get a 'closed form' for $\sum_{k=0}^{n} a_k b_{n-k}$?

Published on 10 Oct 2013 - 20:50

score 79 · Answer 12 · 2013-10-11 15:33:19

79

Views

Laurent series expansion of a function defined by an integral

Published on 11 Oct 2013 - 15:33

score 6.3k · Answer 13 · 2013-10-16 13:29:12

6.3k

Views

Laurent series of $\frac{1-\cos(z)}{z^2}$

Published on 16 Oct 2013 - 13:29

score 821 · Answer 14 · 2013-10-17 03:29:49

821

Views

Deriving the Laurent series

Published on 17 Oct 2013 - 3:29

score 1.8k · Answer 15 · 2013-10-19 17:36:50

1.8k

Views

What is the difference between Taylor series and Laurent series?

Published on 19 Oct 2013 - 17:36

List Question

Find the principal part of the Laurent expansion of $\frac{(z^{2}-2z-3)^{2}}{\cos(\pi z)+1}$ around $z_{0}=1$

Find the Laurant expansion

Laurent Series of the function

Laurent expansion

How to switch to a Laurent series' next convergence ring?

Is there a completion of Laurent series w.r.t. integration?

Laurent series of a trigonometric function

Given a meromorphic function (via its Laurent series), how to obtain the (Taylor series of the) two holomorphic functions it is the quotient of?

Show that $\frac{z}{(z-1)(z-3)} = -3\sum\limits_{n=0}^{\infty}\frac{(z-1)^n}{2^{n+2}} - \frac{1}{2(z-1)}$.

Trouble finding the Laurent Expansion .

Is it possible to get a 'closed form' for $\sum_{k=0}^{n} a_k b_{n-k}$?

Laurent series expansion of a function defined by an integral

Laurent series of $\frac{1-\cos(z)}{z^2}$

Deriving the Laurent series

What is the difference between Taylor series and Laurent series?

Trending Questions

Popular # Hahtags

Popular Questions