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15
Math.TechQA.Club
2017-12-02 00:49:17
55
Views
Finding the Laurent Series of $\frac{1}{z^2(z+1)(z-2)} .$
Published on
02 Dec 2017 - 0:49
#complex-analysis
#laurent-series
53
Views
How to find Laurent expansion of $f(z)=\frac{1}{(z+i)z^2}$ on $0<|z-i|<1$
Published on
02 Dec 2017 - 3:16
#complex-analysis
#laurent-series
445
Views
Expansions in Laurent series exercise
Published on
02 Dec 2017 - 4:36
#complex-analysis
#laurent-series
138
Views
Mathematical Infinite Series - closed form
Published on
02 Dec 2017 - 10:59
#sequences-and-series
#taylor-expansion
#laurent-series
390
Views
Coefficients in Laurent expansion of a function
Published on
02 Dec 2017 - 18:31
#complex-analysis
#residue-calculus
#laurent-series
43
Views
Subsequences with different limits
Published on
03 Dec 2017 - 15:22
#sequences-and-series
#complex-analysis
#convergence-divergence
#laurent-series
967
Views
Laurent Series for different domains
Published on
06 Dec 2017 - 0:50
#laurent-series
197
Views
Finding the largest open set for which a series converges.
Published on
11 Dec 2017 - 7:27
#complex-analysis
#analysis
#laurent-series
108
Views
How do you expand this function around infinity?
Published on
12 Dec 2017 - 0:47
#taylor-expansion
#laurent-series
696
Views
Find the first three nonzero terms in the Laurent series expansion of $f$ in a region
Published on
12 Dec 2017 - 4:20
#complex-analysis
#taylor-expansion
#laurent-series
413
Views
Find annulus of convergence for the following Laurent series
Published on
12 Dec 2017 - 8:36
#complex-analysis
#taylor-expansion
#laurent-series
33
Views
Stuck evaluating Taylor series
Published on
25 Mar 2026 - 12:22
#complex-analysis
#taylor-expansion
#laurent-series
#euler-maclaurin
40
Views
Series manipulations in working out a Laurent series
Published on
13 Dec 2017 - 2:15
#complex-analysis
#laurent-series
902
Views
find all the singular points and residues of given function
Published on
29 Mar 2026 - 2:52
#complex-analysis
#residue-calculus
#laurent-series
#singularity
113
Views
Demonstrate $\frac{1}{2\pi} \int_0^{2\pi} \cos^{2k}(\theta)\,d\theta = \frac{(2k)!}{2^{2k} (k!)^2}$ (problems with the hints)
Published on
17 Dec 2017 - 11:15
#calculus
#complex-analysis
#definite-integrals
#residue-calculus
#laurent-series
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