Question

Is there a well-ordering of the reals whose initial segments are all measurable?

score 326 · Answer 1 · 2026-04-13 01:20:47

326

Views

Is there a well-ordering of the reals whose initial segments are all measurable?

Published on 13 Apr 2026 - 1:20

score 157 · Answer 2 · 2026-04-15 14:32:54

157

Views

A measure space which satisfying $\inf\{\mu(E): E\in M \text{ such that } \mu(E)>0\}=0$

Published on 15 Apr 2026 - 14:32

score 118 · Answer 3 · 2026-04-13 23:54:32

118

Views

How to calculate the Lebesgue measure of the set $\big\{(x,y)\in [0,1]^2:xy\leq 1/2\big\}$?

Published on 13 Apr 2026 - 23:54

score 84 · Answer 4 · 2026-04-12 06:25:51

84

Views

Needle with basis $x$ and lebesgue measure

Published on 12 Apr 2026 - 6:25

score 65 · Answer 5 · 2026-04-12 05:59:07

65

Views

How to prove that the distance $|x-y|$ in $A$ (where $A$ is a subset of $\mathbb{R}$ with positive lebesgue measure) does not belong in the Cantor set

Published on 12 Apr 2026 - 5:59

score 105 · Answer 6 · 2026-04-12 00:03:54

105

Views

Do the normal numbers have Lebesgue measure 1?

Published on 12 Apr 2026 - 0:03

score 30 · Answer 7 · 2026-04-14 06:36:14

30

Views

bounding the measure of some subset of $[0,1]$

Published on 14 Apr 2026 - 6:36

score 69 · Answer 8 · 2026-04-15 07:26:33

69

Views

On the layer cake representation

Published on 15 Apr 2026 - 7:26

score 30 · Answer 9 · 2026-04-16 12:29:50

30

Views

convergence of truncated sequence in $L_{1}$

Published on 16 Apr 2026 - 12:29

score 47 · Answer 10 · 2026-04-16 09:19:03

47

Views

Lebesgue measure of complement of Q-invariant set

Published on 16 Apr 2026 - 9:19

score 72 · Answer 11 · 2026-04-14 10:42:30

72

Views

Am I trying to prove something that isn't even true?

Published on 14 Apr 2026 - 10:42

score 22 · Answer 12 · 2026-04-16 12:15:54

22

Views

Uniform boundedness of sequence of Sobolev extensions

Published on 16 Apr 2026 - 12:15

score 51 · Answer 13 · 2026-04-15 00:38:21

51

Views

If $x \in \mathbb{R}$ is a Lebesgue density point for both measurable subsets $A$ and $B$, then it's also a density point for $A\cap B$.

Published on 15 Apr 2026 - 0:38

score 68 · Answer 14 · 2026-04-17 12:04:59

68

Views

Show $A=\bigcap_{n\in\mathbb{N}}\bigcup_{k\in\mathbb{N}}(q_k-\frac{1}{2^{k+n}},q_k+\frac{1}{2^{k+n}})\subseteq\mathbb{R}$ is a $\lambda^1$ zero set

Published on 17 Apr 2026 - 12:04

score 66 · Answer 15 · 2026-04-12 02:05:26

66

Views

Folland Theorem 3.20

Published on 12 Apr 2026 - 2:05

List Question

Is there a well-ordering of the reals whose initial segments are all measurable?

A measure space which satisfying $\inf\{\mu(E): E\in M \text{ such that } \mu(E)>0\}=0$

How to calculate the Lebesgue measure of the set $\big\{(x,y)\in [0,1]^2:xy\leq 1/2\big\}$?

Needle with basis $x$ and lebesgue measure

How to prove that the distance $|x-y|$ in $A$ (where $A$ is a subset of $\mathbb{R}$ with positive lebesgue measure) does not belong in the Cantor set

Do the normal numbers have Lebesgue measure 1?

bounding the measure of some subset of $[0,1]$

On the layer cake representation

convergence of truncated sequence in $L_{1}$

Lebesgue measure of complement of Q-invariant set

Am I trying to prove something that isn't even true?

Uniform boundedness of sequence of Sobolev extensions

If $x \in \mathbb{R}$ is a Lebesgue density point for both measurable subsets $A$ and $B$, then it's also a density point for $A\cap B$.

Show $A=\bigcap_{n\in\mathbb{N}}\bigcup_{k\in\mathbb{N}}(q_k-\frac{1}{2^{k+n}},q_k+\frac{1}{2^{k+n}})\subseteq\mathbb{R}$ is a $\lambda^1$ zero set

Folland Theorem 3.20

Trending Questions

Popular # Hahtags

Popular Questions