Question

There exists $M \in \mathscr{M}(n \times n,\mathbb{R})$ such that $e^M=L^2$?

score 106 · Answer 1 · 2020-06-24 13:01:06

106

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There exists $M \in \mathscr{M}(n \times n,\mathbb{R})$ such that $e^M=L^2$?

Published on 24 Jun 2020 - 13:01

score 208 · Answer 2 · 2026-03-26 04:31:14

208

Views

Lie Algebras: Root algorithm for the positive roots of $G_2$

Published on 26 Mar 2026 - 4:31

score 255 · Answer 3 · 2020-06-25 12:43:31

255

Views

If all elements of Lie algebra are nilpotent , is the Lie algebra nilpotent?

Published on 25 Jun 2020 - 12:43

score 260 · Answer 4 · 2026-04-05 02:39:43

260

Views

do Carmo Riemannian Geometry Exercise 1.4(b) - The Möbius transformation is an isometry of the Poincaré half plane

Published on 05 Apr 2026 - 2:39

score 673 · Answer 5 · 2026-03-26 04:33:18

673

Views

$SO(p,q)$ Fundamental Weights?

Published on 26 Mar 2026 - 4:33

score 93 · Answer 6 · 2026-03-27 06:26:02

93

Views

Jordan normal form in a reductive group

Published on 27 Mar 2026 - 6:26

score 145 · Answer 7 · 2026-03-25 03:05:38

145

Views

Constructing the root diagram for $B_2$

Published on 25 Mar 2026 - 3:05

score 243 · Answer 8 · 2020-07-01 19:21:28

243

Views

Exercise 12 of Chapter 7 in Brian Hall's Lie groups, Lie algebras and their representation.

Published on 01 Jul 2020 - 19:21

score 563 · Answer 9 · 2026-03-27 23:48:34

563

Views

Why is the realification of a simple complex Lie algebra a semisimple real Lie algebra?

Published on 27 Mar 2026 - 23:48

score 138 · Answer 10 · 2026-03-25 14:23:38

138

Views

Homogeneous space and Uniform Subgroup of Lie groups

Published on 25 Mar 2026 - 14:23

score 343 · Answer 11 · 2026-04-06 13:12:02

343

Views

Deducing the adjoint representation of a Lie algebra from the adjoint representation of the Lie group

Published on 06 Apr 2026 - 13:12

score 80 · Answer 12 · 2026-03-10 11:00:45

80

Views

Cohomology theory for vertex operator algebras?

Published on 10 Mar 2026 - 11:00

score 67 · Answer 13 · 2026-03-31 02:10:23

67

Views

Gabber's analogue of Bernstein inequality for category $\mathcal{O}$

Published on 31 Mar 2026 - 2:10

score 197 · Answer 14 · 2026-03-26 06:13:36

197

Views

If $\lambda \prec \eta$ are positive roots, then there exists another root $\zeta$ such that $\lambda \prec \zeta \prec \eta$.

Published on 26 Mar 2026 - 6:13

score 113 · Answer 15 · 2020-07-07 14:35:28

113

Views

Reference Request: $H^1(\mathfrak g, V)=0$ for semisimple Lie algebra $\mathfrak g$ and $\mathfrak g$-module $V$

Published on 07 Jul 2020 - 14:35

List Question

There exists $M \in \mathscr{M}(n \times n,\mathbb{R})$ such that $e^M=L^2$?

Lie Algebras: Root algorithm for the positive roots of $G_2$

If all elements of Lie algebra are nilpotent , is the Lie algebra nilpotent?

do Carmo Riemannian Geometry Exercise 1.4(b) - The Möbius transformation is an isometry of the Poincaré half plane

$SO(p,q)$ Fundamental Weights?

Jordan normal form in a reductive group

Constructing the root diagram for $B_2$

Exercise 12 of Chapter 7 in Brian Hall's Lie groups, Lie algebras and their representation.

Why is the realification of a simple complex Lie algebra a semisimple real Lie algebra?

Homogeneous space and Uniform Subgroup of Lie groups

Deducing the adjoint representation of a Lie algebra from the adjoint representation of the Lie group

Cohomology theory for vertex operator algebras?

Gabber's analogue of Bernstein inequality for category $\mathcal{O}$

If $\lambda \prec \eta$ are positive roots, then there exists another root $\zeta$ such that $\lambda \prec \zeta \prec \eta$.

Reference Request: $H^1(\mathfrak g, V)=0$ for semisimple Lie algebra $\mathfrak g$ and $\mathfrak g$-module $V$

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