Question

Isomorphic Lie algebras have isomorphic centers

score 247 · Answer 1 · 2026-04-02 18:17:12

247

Views

Isomorphic Lie algebras have isomorphic centers

Published on 02 Apr 2026 - 18:17

score 96 · Answer 2 · 2026-03-25 11:02:49

96

Views

What do you get when you pull the Bruhat Decomposition back to the Lie algebra via the exponential map?

Published on 25 Mar 2026 - 11:02

score 618 · Answer 3 · 2026-03-25 15:58:22

618

Views

Convolution of matrix coefficients is also a matrix coefficients

Published on 25 Mar 2026 - 15:58

score 387 · Answer 4 · 2026-04-02 20:04:31

387

Views

Reference request: classification of simple Lie groups and simple real Lie algebras

Published on 02 Apr 2026 - 20:04

score 152 · Answer 5 · 2014-11-17 10:59:31

152

Views

Clarification of Definition: Free Algebra

Published on 17 Nov 2014 - 10:59

score 197 · Answer 6 · 2014-11-15 03:19:16

197

Views

How can the existence of this expression with Cartan matrix be shown using Killing form?

Published on 15 Nov 2014 - 3:19

score 645 · Answer 7 · 2026-04-02 19:55:36

645

Views

How does one define weights for a semisimple Lie group?

Published on 02 Apr 2026 - 19:55

score 61 · Answer 8 · 2026-04-03 13:53:06

61

Views

Partial generalisation to Whitehead's second Lemma

Published on 03 Apr 2026 - 13:53

score 175 · Answer 9 · 2014-11-19 01:36:43

175

Views

What is a Serre presentation of a Lie algebra?

Published on 19 Nov 2014 - 1:36

score 170 · Answer 10 · 2026-04-02 19:59:43

170

Views

Is the center of a compact Lie algebra precisely the set of vectors on which the Killing form is zero?

Published on 02 Apr 2026 - 19:59

score 945 · Answer 11 · 2014-11-19 16:53:30

945

Views

What is the nilradical of $\mathfrak{gl}_n$?

Published on 19 Nov 2014 - 16:53

score 203 · Answer 12 · 2014-11-19 20:31:53

203

Views

$H^q(\mathfrak{g},K;V)$ is equal to $Ext_{\left(\mathfrak{g},K\right)}^q\left(\mathbb{C},V\right)$?

Published on 19 Nov 2014 - 20:31

score 2.7k · Answer 13 · 2026-03-28 06:41:51

2.7k

Views

The action of a Lie algebra on a manifold is a Lie algebra homomorphism. How to show it?

Published on 28 Mar 2026 - 6:41

score 888 · Answer 14 · 2026-03-26 06:20:54

888

Views

The universal enveloping algebra of free Lie algebra is the tensor algebra on the Free Abelian Group?

Published on 26 Mar 2026 - 6:20

score 33 · Answer 15 · 2026-04-02 19:55:36

33

Views

Normal subgroup invariant under $\text{Ad}_g$

Published on 02 Apr 2026 - 19:55

List Question

Isomorphic Lie algebras have isomorphic centers

What do you get when you pull the Bruhat Decomposition back to the Lie algebra via the exponential map?

Convolution of matrix coefficients is also a matrix coefficients

Reference request: classification of simple Lie groups and simple real Lie algebras

Clarification of Definition: Free Algebra

How can the existence of this expression with Cartan matrix be shown using Killing form?

How does one define weights for a semisimple Lie group?

Partial generalisation to Whitehead's second Lemma

What is a Serre presentation of a Lie algebra?

Is the center of a compact Lie algebra precisely the set of vectors on which the Killing form is zero?

What is the nilradical of $\mathfrak{gl}_n$?

$H^q(\mathfrak{g},K;V)$ is equal to $Ext_{\left(\mathfrak{g},K\right)}^q\left(\mathbb{C},V\right)$?

The action of a Lie algebra on a manifold is a Lie algebra homomorphism. How to show it?

The universal enveloping algebra of free Lie algebra is the tensor algebra on the Free Abelian Group?

Normal subgroup invariant under $\text{Ad}_g$

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