Question

Is it possible to solve this limit without Hopital / Taylor / derivatives: $\lim\limits_{x \to 0} \frac{x-\sin(x)}{x^3} = \frac{1}{6}$?

score 602 · Answer 1 · 2015-10-24 17:41:56

602

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Is it possible to solve this limit without Hopital / Taylor / derivatives: $\lim\limits_{x \to 0} \frac{x-\sin(x)}{x^3} = \frac{1}{6}$?

Published on 24 Oct 2015 - 17:41

score 343 · Answer 2 · 2015-10-25 02:24:44

343

Views

Find $\lim_{x\to0}\frac1{x^3}\left(\left(\frac{2+\cos x}{3}\right)^x-1\right)$ without L'Hopital's rule

Published on 25 Oct 2015 - 2:24

score 134 · Answer 3 · 2015-10-25 21:21:17

134

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Find limit "1 ^ infinity"

Published on 25 Oct 2015 - 21:21

score 813 · Answer 4 · 2026-03-04 05:07:10

813

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Question about evaluating infinite limit, $\lim\limits_{x\to\infty}{\sqrt{1+4x^6}\over 2-x^3}.$

Published on 04 Mar 2026 - 5:07

score 1.3k · Answer 5 · 2015-10-27 16:07:22

1.3k

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Show $n!=\omega(2^n)$ using Stirling's Approximation

Published on 27 Oct 2015 - 16:07

score 76 · Answer 6 · 2015-10-29 15:59:41

76

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Find limit of the expression

Published on 29 Oct 2015 - 15:59

score 72 · Answer 7 · 2015-10-31 17:50:00

72

Views

Compute limit without L'Hospital's rule or derivative

Published on 31 Oct 2015 - 17:50

score 119 · Answer 8 · 2015-11-03 12:15:57

119

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How to rigorously show this limit to be zero?

Published on 03 Nov 2015 - 12:15

score 465 · Answer 9 · 2015-11-03 21:44:07

465

Views

Solving $\lim\limits_{x \to 0}\frac{\ln \cos 3x}{\ln \cos (-x)}$ without L'Hospital rule

Published on 03 Nov 2015 - 21:44

score 137 · Answer 10 · 2015-11-04 16:00:59

137

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How to evaluate $\lim_{x\to\infty}\arctan (4/x)/ |\arcsin (-3/x)|$?

Published on 04 Nov 2015 - 16:00

score 59 · Answer 11 · 2015-11-04 18:06:06

59

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Limit of function $\lim\limits_{x \to - \infty } {{\arcsin (-{5 \over x})} \over {|\tan ({2 \over x})|}}$

Published on 04 Nov 2015 - 18:06

score 917 · Answer 12 · 2015-11-04 18:26:44

917

Views

Limit evaluate $\lim_{x\to0}{{\frac{\ln(\cos(4x))}{\ln(\cos(3x))}}}$?

Published on 04 Nov 2015 - 18:26

score 94 · Answer 13 · 2015-11-04 18:59:37

94

Views

Limit with abs $\lim_{x\to0^-}{\frac{|\tan(-2x)|}{\arcsin(-5x)}}$

Published on 04 Nov 2015 - 18:59

score 386 · Answer 14 · 2015-11-04 22:18:33

386

Views

Limit evaluate $\lim_{x\to0}{{\frac{\ln(\cos(-5x))}{\ln(\cos(-3x))}}}$

Published on 04 Nov 2015 - 22:18

score 59 · Answer 15 · 2015-11-04 22:46:03

59

Views

Limit evaluate $ \lim\limits_{x \to - \infty } {{|\arcsin ({2 \over x})|} \over {\arctan ({5 \over x})}} $

Published on 04 Nov 2015 - 22:46

List Question

Is it possible to solve this limit without Hopital / Taylor / derivatives: $\lim\limits_{x \to 0} \frac{x-\sin(x)}{x^3} = \frac{1}{6}$?

Find $\lim_{x\to0}\frac1{x^3}\left(\left(\frac{2+\cos x}{3}\right)^x-1\right)$ without L'Hopital's rule

Find limit "1 ^ infinity"

Question about evaluating infinite limit, $\lim\limits_{x\to\infty}{\sqrt{1+4x^6}\over 2-x^3}.$

Show $n!=\omega(2^n)$ using Stirling's Approximation

Find limit of the expression

Compute limit without L'Hospital's rule or derivative

How to rigorously show this limit to be zero?

Solving $\lim\limits_{x \to 0}\frac{\ln \cos 3x}{\ln \cos (-x)}$ without L'Hospital rule

How to evaluate $\lim_{x\to\infty}\arctan (4/x)/ |\arcsin (-3/x)|$?

Limit of function $\lim\limits_{x \to - \infty } {{\arcsin (-{5 \over x})} \over {|\tan ({2 \over x})|}}$

Limit evaluate $\lim_{x\to0}{{\frac{\ln(\cos(4x))}{\ln(\cos(3x))}}}$?

Limit with abs $\lim_{x\to0^-}{\frac{|\tan(-2x)|}{\arcsin(-5x)}}$

Limit evaluate $\lim_{x\to0}{{\frac{\ln(\cos(-5x))}{\ln(\cos(-3x))}}}$

Limit evaluate $ \lim\limits_{x \to - \infty } {{|\arcsin ({2 \over x})|} \over {\arctan ({5 \over x})}} $

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