Question

Does global lipschitz imply locally lipschitz?

score 766 · Answer 1 · 2015-11-13 19:57:30

766

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Does global lipschitz imply locally lipschitz?

Published on 13 Nov 2015 - 19:57

score 1.8k · Answer 2 · 2026-03-27 15:13:24

1.8k

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Barycenter of a measure

Published on 27 Mar 2026 - 15:13

score 232 · Answer 3 · 2015-11-17 14:19:08

232

Views

A continuous selection from a countable family of uniformly Lipschitz functions is Lipschitz

Published on 17 Nov 2015 - 14:19

score 38 · Answer 4 · 2015-11-21 14:14:37

38

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Definition of $l^{\infty}(\widetilde{X})$

Published on 21 Nov 2015 - 14:14

score 322 · Answer 5 · 2015-11-22 14:00:55

322

Views

Uniform convergence from pointwise convergence for uniform Lipshitz functions

Published on 22 Nov 2015 - 14:00

score 1.2k · Answer 6 · 2015-11-23 00:59:15

1.2k

Views

Continuous and increasing on $[0,1]$ and absolutely continuous on $[\varepsilon,1] \forall \varepsilon >0 =>$ absolutely continuous on $[0,1]$?

Published on 23 Nov 2015 - 0:59

score 139 · Answer 7 · 2015-11-23 08:14:21

139

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Bounded linear functional $\phi \in Lip_0(X)^$ belongs to the predual of $Lip_0(X)$ iff it is continuous with respect to the weak$^$ topology

Published on 23 Nov 2015 - 8:14

score 150 · Answer 8 · 2015-11-25 13:37:36

150

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(dis)prove:$\sup_{F \in 2^{(L^1(S,\mathbb{R}))}}\limsup\sup_{f\in F}|\int f dP_n-\int fdP|=\limsup\sup_{f\in L^1(S,\mathbb{R})}|\int fdP_n-\int fdP|$

Published on 25 Nov 2015 - 13:37

score 121 · Answer 9 · 2015-11-25 20:09:35

121

Views

Showing that a function is Lipschitz

Published on 25 Nov 2015 - 20:09

score 830 · Answer 10 · 2015-11-26 05:02:04

830

Views

Prove that $\frac{f(x)}{x}$ is uniformly continuous in $[1, +∞)$ if $f$ is Lipschitz

Published on 26 Nov 2015 - 5:02

score 263 · Answer 11 · 2015-11-27 01:07:40

263

Views

Relationship between $c_0$ and $C(K)$

Published on 27 Nov 2015 - 1:07

score 473 · Answer 12 · 2015-11-27 06:18:07

473

Views

Examples of little Lipschitz functions

Published on 27 Nov 2015 - 6:18

score 99 · Answer 13 · 2015-11-29 15:03:09

99

Views

Prove that $lip_0(K)$ is separating if and only if it is weak$^*$-dense in $Lip_0(K)$.

Published on 29 Nov 2015 - 15:03

score 300 · Answer 14 · 2015-11-30 05:11:23

300

Views

Necessary theory to understand differentiable function approximation by lipschitz continuous functions

Published on 30 Nov 2015 - 5:11

score 730 · Answer 15 · 2015-12-01 04:17:31

730

Views

Does Globally Lipchitz prove a solution exists for all time?

Published on 01 Dec 2015 - 4:17

List Question

Does global lipschitz imply locally lipschitz?

Barycenter of a measure

A continuous selection from a countable family of uniformly Lipschitz functions is Lipschitz

Definition of $l^{\infty}(\widetilde{X})$

Uniform convergence from pointwise convergence for uniform Lipshitz functions

Continuous and increasing on $[0,1]$ and absolutely continuous on $[\varepsilon,1] \forall \varepsilon >0 =>$ absolutely continuous on $[0,1]$?

Bounded linear functional $\phi \in Lip_0(X)^$ belongs to the predual of $Lip_0(X)$ iff it is continuous with respect to the weak$^$ topology

(dis)prove:$\sup_{F \in 2^{(L^1(S,\mathbb{R}))}}\limsup\sup_{f\in F}|\int f dP_n-\int fdP|=\limsup\sup_{f\in L^1(S,\mathbb{R})}|\int fdP_n-\int fdP|$

Showing that a function is Lipschitz

Prove that $\frac{f(x)}{x}$ is uniformly continuous in $[1, +∞)$ if $f$ is Lipschitz

Relationship between $c_0$ and $C(K)$

Examples of little Lipschitz functions

Prove that $lip_0(K)$ is separating if and only if it is weak$^*$-dense in $Lip_0(K)$.

Necessary theory to understand differentiable function approximation by lipschitz continuous functions

Does Globally Lipchitz prove a solution exists for all time?

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