Question

Representing a logarithmic graph as a percentage by tending to 100

score 90 · Answer 1 · 2026-04-13 15:03:50

90

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Representing a logarithmic graph as a percentage by tending to 100

Published on 13 Apr 2026 - 15:03

score 333 · Answer 2 · 2026-04-16 08:45:53

333

Views

Is there a convention to express: $~\log(\log(x))~$?

Published on 16 Apr 2026 - 8:45

score 23 · Answer 3 · 2026-04-16 04:36:55

23

Views

calculate constants $a$ and $c$

Published on 16 Apr 2026 - 4:36

score 68 · Answer 4 · 2026-04-15 00:12:38

68

Views

Logarithms: How to solve for $x$ in $(\sqrt{2}/2)^x = 2$

Published on 15 Apr 2026 - 0:12

score 82 · Answer 5 · 2026-03-25 15:38:53

82

Views

Solving $y = x + \log_2x$ for $x$

Published on 25 Mar 2026 - 15:38

score 50 · Answer 6 · 2026-04-17 13:31:17

50

Views

Logarithmic inequation $\frac{3^{x+1}}{2^{x+3}}+2\leq \frac{2^{x-1}}{3^{x-1}}$

Published on 17 Apr 2026 - 13:31

score 67 · Answer 7 · 2026-04-15 16:53:57

67

Views

Why isn't $\ln^{\ln (x)}(x)$ defined for $(-\infty,1)$?

Published on 15 Apr 2026 - 16:53

score 92 · Answer 8 · 2026-04-17 07:03:12

92

Views

Logarithm inequality $\log (25 + 5^{2x}) > x(1-\log 2) + \log 2 + \log13$

Published on 17 Apr 2026 - 7:03

score 39 · Answer 9 · 2026-04-11 20:50:51

39

Views

Logarithm on absolute values

Published on 11 Apr 2026 - 20:50

score 26 · Answer 10 · 2026-04-16 17:01:49

26

Views

log base and parameter switch property

Published on 16 Apr 2026 - 17:01

score 47 · Answer 11 · 2026-04-15 05:58:21

47

Views

I have an exam tomorrow and can't seem to solve this Logarithmic Equations question.

Published on 15 Apr 2026 - 5:58

score 46 · Answer 12 · 2026-04-16 08:41:31

46

Views

Is a function like $\log_\sqrt{x} x $ defined in the point $x_0 = 1$?

Published on 16 Apr 2026 - 8:41

score 51 · Answer 13 · 2026-04-17 11:43:39

51

Views

Logarithmic inequality $5\times \frac{3^{x-2}}{3^{x}-2^{x}}\geq1+(\frac{2}{3})^x$

Published on 17 Apr 2026 - 11:43

score 98 · Answer 14 · 2026-04-16 04:34:29

98

Views

Prove inequality $0< \frac{1}{n} \ -\ln\left( 1+\frac{1}{n} \right) < \frac{1}{2n^{2}}$ using Taylor polynomial

Published on 16 Apr 2026 - 4:34

score 65 · Answer 15 · 2026-04-09 14:47:05

65

Views

A question regarding Euler's number, Riemann's zeta function and the prime-number theorem

Published on 09 Apr 2026 - 14:47

List Question

Representing a logarithmic graph as a percentage by tending to 100

Is there a convention to express: $~\log(\log(x))~$?

calculate constants $a$ and $c$

Logarithms: How to solve for $x$ in $(\sqrt{2}/2)^x = 2$

Solving $y = x + \log_2x$ for $x$

Logarithmic inequation $\frac{3^{x+1}}{2^{x+3}}+2\leq \frac{2^{x-1}}{3^{x-1}}$

Why isn't $\ln^{\ln (x)}(x)$ defined for $(-\infty,1)$?

Logarithm inequality $\log (25 + 5^{2x}) > x(1-\log 2) + \log 2 + \log13$

Logarithm on absolute values

log base and parameter switch property

I have an exam tomorrow and can't seem to solve this Logarithmic Equations question.

Is a function like $\log_\sqrt{x} x $ defined in the point $x_0 = 1$?

Logarithmic inequality $5\times \frac{3^{x-2}}{3^{x}-2^{x}}\geq1+(\frac{2}{3})^x$

Prove inequality $0< \frac{1}{n} \ -\ln\left( 1+\frac{1}{n} \right) < \frac{1}{2n^{2}}$ using Taylor polynomial

A question regarding Euler's number, Riemann's zeta function and the prime-number theorem

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