Question

Weak convergence of $f_n$ in $L^p$ implies that of $|f_n|$?

score 190 · Answer 1 · 2020-05-10 07:40:07

190

Views

Weak convergence of $f_n$ in $L^p$ implies that of $|f_n|$?

Published on 10 May 2020 - 7:40

score 445 · Answer 2 · 2020-05-10 08:53:58

445

Views

$L^p$ for $0<p<1$ is not a normed space

Published on 10 May 2020 - 8:53

score 47 · Answer 3 · 2020-05-11 11:28:28

47

Views

Showing an inequality with the subgaussian and Lp norm, and also showing that $\|X\|_2$ is subgaussian.

Published on 11 May 2020 - 11:28

score 157 · Answer 4 · 2020-05-12 13:23:47

157

Views

Weak convergence of $\Bigl(\sum\limits_{k=n}^\infty e_k\Bigr)_n$

Published on 12 May 2020 - 13:23

score 91 · Answer 5 · 2020-05-13 19:31:30

91

Views

When is $C_{\mathbb{C}}(\Omega)$ dense in $L_{\mathbb{C}}^{2}(\Omega,\mu)$ with respect to the $L^{2}$-norm?

Published on 13 May 2020 - 19:31

score 102 · Answer 6 · 2026-03-26 12:46:11

102

Views

$L^1$ convergence rate of convolution with gaussian

Published on 26 Mar 2026 - 12:46

score 83 · Answer 7 · 2026-03-30 09:48:27

83

Views

Approximating by convolution a function $f \in L^1(\mathbb{R})$ such that $\hat{f} \in L^1(\mathbb{R})$.

Published on 30 Mar 2026 - 9:48

score 39 · Answer 8 · 2020-05-17 18:37:40

39

Views

Bounded sequence in spaces with variable exponent

Published on 17 May 2020 - 18:37

score 29 · Answer 9 · 2026-03-25 12:46:30

29

Views

Computing $L^2$ norm on a curved domain

Published on 25 Mar 2026 - 12:46

score 3.4k · Answer 10 · 2020-05-18 13:18:42

3.4k

Views

$L^p$ space, simple function and density.

Published on 18 May 2020 - 13:18

score 73 · Answer 11 · 2020-05-18 15:57:44

73

Views

Total boundedness of $K \subset \ell^1$, iff $K$ is uniformly summable & bounded

Published on 18 May 2020 - 15:57

score 54 · Answer 12 · 2020-05-18 18:51:37

54

Views

What is the right Lebesgue space $L^p_{loc}(\mathbb{R}^3)$ to which the function $\frac{1}{\vert x\vert}$ belongs?

Published on 18 May 2020 - 18:51

score 213 · Answer 13 · 2026-03-26 01:34:59

213

Views

The space of bounded linear map from $L^2(\mathbb{R})$ to $L^2(\mathbb{R})$ is not separable.

Published on 26 Mar 2026 - 1:34

score 232 · Answer 14 · 2026-03-27 07:13:50

232

Views

Spectrum of a $\ell^2$ operator and compactness

Published on 27 Mar 2026 - 7:13

score 41 · Answer 15 · 2020-05-20 09:27:20

41

Views

replace supremum by a sequence

Published on 20 May 2020 - 9:27

List Question

Weak convergence of $f_n$ in $L^p$ implies that of $|f_n|$?

$L^p$ for $0<p<1$ is not a normed space

Showing an inequality with the subgaussian and Lp norm, and also showing that $\|X\|_2$ is subgaussian.

Weak convergence of $\Bigl(\sum\limits_{k=n}^\infty e_k\Bigr)_n$

When is $C_{\mathbb{C}}(\Omega)$ dense in $L_{\mathbb{C}}^{2}(\Omega,\mu)$ with respect to the $L^{2}$-norm?

$L^1$ convergence rate of convolution with gaussian

Approximating by convolution a function $f \in L^1(\mathbb{R})$ such that $\hat{f} \in L^1(\mathbb{R})$.

Bounded sequence in spaces with variable exponent

Computing $L^2$ norm on a curved domain

$L^p$ space, simple function and density.

Total boundedness of $K \subset \ell^1$, iff $K$ is uniformly summable & bounded

What is the right Lebesgue space $L^p_{loc}(\mathbb{R}^3)$ to which the function $\frac{1}{\vert x\vert}$ belongs?

The space of bounded linear map from $L^2(\mathbb{R})$ to $L^2(\mathbb{R})$ is not separable.

Spectrum of a $\ell^2$ operator and compactness

replace supremum by a sequence

Trending Questions

Popular # Hahtags

Popular Questions