List questions from matrix-rank

Published on 20 Feb 2016 - 15:42

262

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Linear system of equations including full rank matrices

Published on 21 Feb 2016 - 20:21

513

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Examples of rank subadditivity equality

Published on 22 Feb 2016 - 11:41

7.9k

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Find all possible values of rank(A) as 'a' varies

Published on 22 Feb 2016 - 14:21

365

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Matrix rank inequality

Published on 22 Feb 2016 - 18:53

56

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Is it possible to get a simplified expression for the following matrix?

Published on 23 Feb 2016 - 13:24

838

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Proving that the rank and nullity of a transformation equals the rank and nullity of a left multiplication transformation

Published on 28 Feb 2016 - 17:56

71

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Why does $\operatorname{rank}([u_{n-k+1},...,u_n][v_{n-k+1},...,v_n]^*)=k$?

Published on 04 Mar 2016 - 3:15

234

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Rank of matrices.

Published on 29 Mar 2026 - 18:08

265

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Does $\text{rank}(AB) = \text{rank}(BA) = r$?

Published on 05 Mar 2016 - 12:49

60

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Rank of a Matrix that Lies in Left Null Space of Another Matrix

Published on 06 Mar 2016 - 19:32

1.4k

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Rank of a block matrix

Published on 07 Mar 2016 - 11:26

12.1k

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Rank of an Augmented matrix

Published on 07 Mar 2016 - 15:02

1.5k

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Matrix rank and concatenation

Published on 07 Mar 2016 - 15:39

1.3k

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Show that Ax = b is solvable when [A b] is singular.

Published on 09 Mar 2016 - 22:34

List Question

Finding all possible ranks of matrix $A$ as $a$ varies?

Linear system of equations including full rank matrices

Examples of rank subadditivity equality

Find all possible values of rank(A) as 'a' varies

Matrix rank inequality

Is it possible to get a simplified expression for the following matrix?

Proving that the rank and nullity of a transformation equals the rank and nullity of a left multiplication transformation

Why does $\operatorname{rank}([u_{n-k+1},...,u_n][v_{n-k+1},...,v_n]^*)=k$?

Rank of matrices.

Does $\text{rank}(AB) = \text{rank}(BA) = r$?

Rank of a Matrix that Lies in Left Null Space of Another Matrix

Rank of a block matrix

Rank of an Augmented matrix

Matrix rank and concatenation

Show that Ax = b is solvable when [A b] is singular.

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