List questions from matroids

Published on 30 Jul 2023 - 17:32

46

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A matroid that is graphic in characteristic 2 but not in characteristic 3

Published on 14 Aug 2023 - 19:19

97

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A matroid with zero Euler characteristic has an isthmus

Published on 01 Sep 2023 - 10:00

45

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what is the quickest way of finding the set of all linearly independent sets over GF(2) and GF(3)?

Published on 23 Feb 2026 - 12:09

110

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How to show that $M_2[A]$ is graphic but $M_3[A]$ is not?

Published on 06 Sep 2023 - 7:11

99

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why So $C_4 \subseteq C_2$?

Published on 06 Sep 2023 - 13:01

96

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Proving $r_{(k)}(X \cup Y) + r_{(k)}(X \cap Y) \leq r_{(k)}(X) + r_{(k)}(Y).$

Published on 08 Sep 2023 - 9:48

36

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Characterizing paving matroids in terms of their bases.

Published on 16 Sep 2023 - 14:21

92

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proving that $r(X \cup Y) = r(X \cup cl(Y)).$

Published on 27 Sep 2023 - 23:53

89

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proving that $r(X \cup cl(Y)) = r(cl(X) \cup cl(Y)).$

Published on 28 Sep 2023 - 0:02

63

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Proving that $r(cl(X) \cup cl(Y)) = r(cl(X \cup Y))$.

Published on 28 Sep 2023 - 0:40

102

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If $X \subseteq Y$ and $r(X) = r(Y),$ then $cl(X) = cl(Y).$

Published on 02 Oct 2023 - 0:11

153

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circuit and a cocircuit can not have an odd number of common elements.

Published on 07 Oct 2023 - 2:41

37

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$e \in C,$ then $e$ is a loop of $M,$ or $C - e$ is a circuit of $M/e.$

Published on 09 Oct 2023 - 14:15

113

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Why does the greedy algorithm work when simplifying fractions?

Published on 10 Oct 2023 - 22:18

List Question

Which quadrants can a codimension 3 subspace intersect?

A matroid that is graphic in characteristic 2 but not in characteristic 3

A matroid with zero Euler characteristic has an isthmus

what is the quickest way of finding the set of all linearly independent sets over GF(2) and GF(3)?

How to show that $M_2[A]$ is graphic but $M_3[A]$ is not?

why So $C_4 \subseteq C_2$?

Proving $r_{(k)}(X \cup Y) + r_{(k)}(X \cap Y) \leq r_{(k)}(X) + r_{(k)}(Y).$

Characterizing paving matroids in terms of their bases.

proving that $r(X \cup Y) = r(X \cup cl(Y)).$

proving that $r(X \cup cl(Y)) = r(cl(X) \cup cl(Y)).$

Proving that $r(cl(X) \cup cl(Y)) = r(cl(X \cup Y))$.

If $X \subseteq Y$ and $r(X) = r(Y),$ then $cl(X) = cl(Y).$

circuit and a cocircuit can not have an odd number of common elements.

$e \in C,$ then $e$ is a loop of $M,$ or $C - e$ is a circuit of $M/e.$

Why does the greedy algorithm work when simplifying fractions?

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