Question

The set of values of $p$ for which the points of extremum of the function $f(x)=x^3-3px^2+3(p^2-1)x+1$ lie in the interval $(-2,4)$

score 1.5k · Answer 1 · 2017-06-28 15:37:34

The set of values of $p$ for which the points of extremum of the function $f(x)=x^3-3px^2+3(p^2-1)x+1$ lie in the interval $(-2,4)$

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List Question

The set of values of $p$ for which the points of extremum of the function $f(x)=x^3-3px^2+3(p^2-1)x+1$ lie in the interval $(-2,4)$

Minimun volume of a tetrahedron bounded by an ellipsoid and tangent plane

What is the minimum value of $A$?

Show that the critical point of this function is a global minimum (geometric median)

Maximum value of a function. I am not able to check double derivative.

Solving a k-order polynomial with constraints.

Find the minimum value of $P=\sum _{cyc}\frac{\left(x+1\right)^2\left(y+1\right)^2}{z^2+1}$

Find the Maximum for Floor function

Minimum on all the lines is local minimum for $C^1$ functions?

Find The Maximum Of $|z^2-3z+2|$ at $|z|\leq 1$

The local property of a function has non-vanishing partial derivative of third order?

Cal1 Cosine Extrema On Interval

Find the minimize value of $A=\frac{1}{\sqrt{a^2+b^2+c^2+1}}-\frac{2}{(a+1)(b+1)(c+1)}$

minimax without choice

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