Question

If for all $\epsilon>0$, there exists $\delta>0$ such that $E[1_A|X|]<\epsilon$ for all measurable $P(A)<\delta$, then $E|X|<\infty$

score 45 · Answer 1 · 2026-05-10 20:26:48

If for all $\epsilon>0$, there exists $\delta>0$ such that $E[1_A|X|]<\epsilon$ for all measurable $P(A)<\delta$, then $E|X|<\infty$

score 2.8k · Answer 2 · 2026-05-10 17:59:26

2.8k

Views

Proof borel sets are measurable sets

Published on 10 May 2026 - 17:59

score 112 · Answer 3 · 2026-05-10 18:06:17

112

Views

Rotations of Lebesgue measurable sets are Lebesgue measurable

Published on 10 May 2026 - 18:06

score 40 · Answer 4 · 2026-05-10 14:59:49

40

Views

Especifying a measurable space for a homogeneos Poisson process.

Published on 10 May 2026 - 14:59

score 259 · Answer 5 · 2026-05-10 18:04:19

259

Views

Question on Lebesgue measure and outer measure

Published on 10 May 2026 - 18:04

score 329 · Answer 6 · 2026-05-10 14:18:43

329

Views

Can an integral defined by a density with respect to folner sequences of $A$ exist on a function defined on subsets of $A$?

Published on 10 May 2026 - 14:18

score 82 · Answer 7 · 2026-05-10 19:10:00

82

Views

$F=(A^c \cup B \cup C)\cap(A\cup C^c)$

Published on 10 May 2026 - 19:10

score 22 · Answer 8 · 2026-05-10 18:06:17

22

Views

Measurablity of single maps from measurability of a composition

Published on 10 May 2026 - 18:06

score 139 · Answer 9 · 2026-05-10 18:06:35

139

Views

Lebesgue outer measure of a subset is equal to outer measure of containing set

Published on 10 May 2026 - 18:06

score 171 · Answer 10 · 2026-05-10 18:04:26

171

Views

Is the $\sigma$-algebra generated by the Carathéodory condition maximal?

Published on 10 May 2026 - 18:04

score 157 · Answer 11 · 2026-05-10 17:38:18

157

Views

Regarding definition of Borel Sets is $ \sigma $ ring of sets

Published on 10 May 2026 - 17:38

score 88 · Answer 12 · 2026-05-10 18:04:00

88

Views

If the union is measurable, so each set is measurable?

Published on 10 May 2026 - 18:04

score 1k · Answer 13 · 2026-05-10 17:57:13

1k

Views

Every interval is measurable.

Published on 10 May 2026 - 17:57

score 255 · Answer 14 · 2026-04-21 08:28:55

255

Views

How does the frequentist definition of probability work with non-measurable sets?

Published on 21 Apr 2026 - 8:28

score 44 · Answer 15 · 2026-05-10 18:05:40

44

Views

Proving that $m((-\infty, x] \cap K) \setminus m((-\infty , y] \cap K) = m((x, y] \cap K),$ where $K$ is a compact set.

Published on 10 May 2026 - 18:05

List Question

If for all $\epsilon>0$, there exists $\delta>0$ such that $E[1_A|X|]<\epsilon$ for all measurable $P(A)<\delta$, then $E|X|<\infty$

Proof borel sets are measurable sets

Rotations of Lebesgue measurable sets are Lebesgue measurable

Especifying a measurable space for a homogeneos Poisson process.

Question on Lebesgue measure and outer measure

Can an integral defined by a density with respect to folner sequences of $A$ exist on a function defined on subsets of $A$?

$F=(A^c \cup B \cup C)\cap(A\cup C^c)$

Measurablity of single maps from measurability of a composition

Lebesgue outer measure of a subset is equal to outer measure of containing set

Is the $\sigma$-algebra generated by the Carathéodory condition maximal?

Regarding definition of Borel Sets is $ \sigma $ ring of sets

If the union is measurable, so each set is measurable?

Every interval is measurable.

How does the frequentist definition of probability work with non-measurable sets?

Proving that $m((-\infty, x] \cap K) \setminus m((-\infty , y] \cap K) = m((x, y] \cap K),$ where $K$ is a compact set.

Trending Questions

Popular # Hahtags

Popular Questions