Question

If $E$ is Lebesgue-measurable, then Borel sets exist with $B_1 \subset E \subset B_2$

score 487 · Answer 1 · 2026-04-16 00:23:02

487

Views

If $E$ is Lebesgue-measurable, then Borel sets exist with $B_1 \subset E \subset B_2$

Published on 16 Apr 2026 - 0:23

score 64 · Answer 2 · 2026-04-12 10:15:37

64

Views

Definition of independence of random variables.

Published on 12 Apr 2026 - 10:15

score 391 · Answer 3 · 2026-04-14 07:09:47

391

Views

Relation between the concept of Contiguity and Absolutely Continuous Measures

Published on 14 Apr 2026 - 7:09

score 337 · Answer 4 · 2026-04-16 16:14:11

337

Views

$E \subset X$ and $\mu ^* (E)=0$, then $E$ is $\mu^*$measurable

Published on 16 Apr 2026 - 16:14

score 1.6k · Answer 5 · 2026-04-15 04:04:26

1.6k

Views

Sigma Algebra generated by a finite number of subsets of P(X) is finite

Published on 15 Apr 2026 - 4:04

score 24 · Answer 6 · 2026-04-11 07:14:57

24

Views

In the two cases below it is possible to define the measure of Borel Stieltjes

Published on 11 Apr 2026 - 7:14

score 155 · Answer 7 · 2026-04-13 21:44:20

155

Views

What is exactly meant with $\int f d\mu=\sup_{\rho \in \Phi^{+}_{f}}\int\rho d\mu$? Why supremum?

Published on 13 Apr 2026 - 21:44

score 95 · Answer 8 · 2026-04-15 12:55:40

95

Views

Evaluate Integrals Using Convergence Theorems

Published on 15 Apr 2026 - 12:55

score 380 · Answer 9 · 2026-04-29 15:21:18

380

Views

Projective limit of spaces of probability measures is bijective to the space of probability measures on a projective limit.

Published on 29 Apr 2026 - 15:21

score 438 · Answer 10 · 2026-04-16 07:18:10

438

Views

Example of a Lebesgue measurable set that can't be constructed from Borel sets and projections?

Published on 16 Apr 2026 - 7:18

score 205 · Answer 11 · 2026-04-16 06:39:54

205

Views

Show $\int_A g\ d\mu = \int_A f\ d\mu$ for $A$ in a sub sigma algebra

Published on 16 Apr 2026 - 6:39

score 478 · Answer 12 · 2026-04-14 21:11:16

478

Views

Does the pointwise limit of a sequence {$f_{n}$} of measurable functions imply that f is measurable? [Graduate studies]

Published on 14 Apr 2026 - 21:11

score 72 · Answer 13 · 2026-04-14 01:50:29

72

Views

measurable function and inverse image not measurable set.

Published on 14 Apr 2026 - 1:50

score 45 · Answer 14 · 2026-04-13 09:26:25

45

Views

Does the Markov property of a Random Variable allow us to say that the expected value of the future is independent of the past, given the present?

Published on 13 Apr 2026 - 9:26

score 1.5k · Answer 15 · 2026-04-15 07:25:38

1.5k

Views

If f is a monotone function which defined on interval, then f is measurable

Published on 15 Apr 2026 - 7:25

List Question

If $E$ is Lebesgue-measurable, then Borel sets exist with $B_1 \subset E \subset B_2$

Definition of independence of random variables.

Relation between the concept of Contiguity and Absolutely Continuous Measures

$E \subset X$ and $\mu ^* (E)=0$, then $E$ is $\mu^*$measurable

Sigma Algebra generated by a finite number of subsets of P(X) is finite

In the two cases below it is possible to define the measure of Borel Stieltjes

What is exactly meant with $\int f d\mu=\sup_{\rho \in \Phi^{+}_{f}}\int\rho d\mu$? Why supremum?

Evaluate Integrals Using Convergence Theorems

Projective limit of spaces of probability measures is bijective to the space of probability measures on a projective limit.

Example of a Lebesgue measurable set that can't be constructed from Borel sets and projections?

Show $\int_A g\ d\mu = \int_A f\ d\mu$ for $A$ in a sub sigma algebra

Does the pointwise limit of a sequence {$f_{n}$} of measurable functions imply that f is measurable? [Graduate studies]

measurable function and inverse image not measurable set.

Does the Markov property of a Random Variable allow us to say that the expected value of the future is independent of the past, given the present?

If f is a monotone function which defined on interval, then f is measurable

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