Question

$\left\{x:\mu(\left\{x\right\})>0\right\}$ is countable.

score 97 · Answer 1 · 2026-04-16 08:51:35

97

Views

$\left\{x:\mu(\left\{x\right\})>0\right\}$ is countable.

Published on 16 Apr 2026 - 8:51

score 158 · Answer 2 · 2026-04-14 18:37:57

158

Views

$\mu$ pure point measure if and only if $\mu(A)=\sum_{x\in A} \mu(\left\{x\right\})$

Published on 14 Apr 2026 - 18:37

score 45 · Answer 3 · 2026-04-13 08:27:29

45

Views

Lebesgue integral simple function query

Published on 13 Apr 2026 - 8:27

score 237 · Answer 4 · 2026-04-16 12:25:03

237

Views

$\frac{1}{||x||^n}$ is integrable on complement of $B(0,a) \subset \mathbb{R}^n$

Published on 16 Apr 2026 - 12:25

score 25 · Answer 5 · 2026-04-12 08:55:21

25

Views

Finite measure space suspected property

Published on 12 Apr 2026 - 8:55

score 74 · Answer 6 · 2026-04-09 16:04:57

74

Views

Linear Operator , visual meaning.

Published on 09 Apr 2026 - 16:04

score 59 · Answer 7 · 2026-04-13 15:47:23

59

Views

An example of weakly convergent probability measures that do not form a family of relatively compact probability measures.

Published on 13 Apr 2026 - 15:47

score 118 · Answer 8 · 2026-04-08 20:44:58

118

Views

Caratheodory measure problem

Published on 08 Apr 2026 - 20:44

score 141 · Answer 9 · 2026-04-16 01:10:21

141

Views

Proof of $\int_{\mathbb{R}^d} f(x) dx = \prod_{i = 1}^{d} \int_{\mathbb{R}} \phi_i(x_i) dx_i$, where $f := \bigotimes_{i = 1}^{d} \phi_i$.

Published on 16 Apr 2026 - 1:10

score 98 · Answer 10 · 2026-04-17 11:32:29

98

Views

If $(X, \mathbb{X}, \mu)$ space of finite measure. $f_n\to f$ in measure implies $f_n\to f$ almost uniformly.

Published on 17 Apr 2026 - 11:32

score 51 · Answer 11 · 2026-05-13 11:24:22

51

Views

First Variation of CDF inside an Indicator Function

Published on 13 May 2026 - 11:24

score 273 · Answer 12 · 2026-05-10 16:09:59

273

Views

Problem 2. A comprehensive course in Analysis. Barry simon. Page 239.

Published on 10 May 2026 - 16:09

score 93 · Answer 13 · 2026-04-15 06:10:28

93

Views

Why is my proof that $L^1(\nu) = L^1(|\nu|)$ for signed measure $\nu$ incorrect?

Published on 15 Apr 2026 - 6:10

score 124 · Answer 14 · 2026-04-11 08:02:24

124

Views

Probability Measures, and inequalities

Published on 11 Apr 2026 - 8:02

score 144 · Answer 15 · 2026-05-10 20:54:01

144

Views

Extension of a von Neumann algebra by a von Neumann algebra

Published on 10 May 2026 - 20:54

List Question

$\left\{x:\mu(\left\{x\right\})>0\right\}$ is countable.

$\mu$ pure point measure if and only if $\mu(A)=\sum_{x\in A} \mu(\left\{x\right\})$

Lebesgue integral simple function query

$\frac{1}{||x||^n}$ is integrable on complement of $B(0,a) \subset \mathbb{R}^n$

Finite measure space suspected property

Linear Operator , visual meaning.

An example of weakly convergent probability measures that do not form a family of relatively compact probability measures.

Caratheodory measure problem

Proof of $\int_{\mathbb{R}^d} f(x) dx = \prod_{i = 1}^{d} \int_{\mathbb{R}} \phi_i(x_i) dx_i$, where $f := \bigotimes_{i = 1}^{d} \phi_i$.

If $(X, \mathbb{X}, \mu)$ space of finite measure. $f_n\to f$ in measure implies $f_n\to f$ almost uniformly.

First Variation of CDF inside an Indicator Function

Problem 2. A comprehensive course in Analysis. Barry simon. Page 239.

Why is my proof that $L^1(\nu) = L^1(|\nu|)$ for signed measure $\nu$ incorrect?

Probability Measures, and inequalities

Extension of a von Neumann algebra by a von Neumann algebra

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