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15
Math.TechQA.Club
2019-11-19 16:55:17
136
Views
Any subset of associated primes of a module M is $\text{Ass}_R(N)$ for some sub-module $N$ of $M$.
Published on
19 Nov 2019 - 16:55
#commutative-algebra
#modules
173
Views
Is the following ring (artinian) semisimple? And are any of these attempts valid?
Published on
23 Feb 2026 - 2:15
#abstract-algebra
#ring-theory
#modules
#artinian
#semi-simple-rings
41
Views
Why $(r+(p))(a+pA) = ra+pA$ holds?
Published on
19 Nov 2019 - 21:00
#abstract-algebra
#ring-theory
#modules
82
Views
Proving cardinality of basis in Module theory
Published on
19 Nov 2019 - 21:20
#abstract-algebra
#ring-theory
#modules
31
Views
Surjection of kernels of a finite $A$-module endomorphism and induced free endomorphism.
Published on
20 Nov 2019 - 1:37
#commutative-algebra
#modules
130
Views
$M'\to M \to M''\to 0$ is exact
Published on
26 Mar 2026 - 20:40
#modules
#exact-sequence
174
Views
Modules: monos are stable under pushouts
Published on
27 Mar 2026 - 14:33
#category-theory
#modules
#abelian-categories
#monomorphisms
258
Views
R-R bimodule definition
Published on
08 Apr 2026 - 6:36
#abstract-algebra
#ring-theory
#modules
35
Views
Showing module can be decomposed
Published on
21 Nov 2019 - 20:44
#abstract-algebra
#modules
46
Views
Consequences of Proposition 1.1 on Semi-inner-product $A$-modules
Published on
30 Mar 2026 - 8:59
#functional-analysis
#modules
#operator-algebras
#c-star-algebras
87
Views
$\mathrm{Hom}(N,\bullet)$ is a functor from (($R$-alg)) to ((?))
Published on
23 Nov 2019 - 6:17
#commutative-algebra
#category-theory
#modules
79
Views
Show that if $M = M_1 \oplus \cdots \oplus M_n$ then $T(M) = T(M_1) \oplus \cdots \oplus T(M_n)$
Published on
23 Nov 2019 - 6:19
#abstract-algebra
#proof-verification
#modules
119
Views
$K[X]$ module and characteristic polynomial
Published on
23 Nov 2019 - 8:34
#linear-algebra
#polynomials
#vector-spaces
#modules
149
Views
Module over skew polynomial ring
Published on
25 Mar 2026 - 15:54
#abstract-algebra
#ring-theory
#modules
#polynomial-rings
180
Views
$p\mathbb{Z}$ is not a direct summand of $\mathbb{Z}$
Published on
23 Nov 2019 - 11:39
#abstract-algebra
#modules
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