Question

Is a functor that is injective on both objects and morphisms at the same time an embedding functor?

score 76 · Answer 1 · 2021-06-04 10:36:53

76

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Is a functor that is injective on both objects and morphisms at the same time an embedding functor?

Published on 04 Jun 2021 - 10:36

score 402 · Answer 2 · 2021-07-14 23:09:32

402

Views

Attempt to define the notion of subobjects

Published on 14 Jul 2021 - 23:09

score 86 · Answer 3 · 2021-07-19 08:01:38

86

Views

Milne, Elliptic Curves, Theorem 2.1 b), Correctly Stated? - Verifying Something is an Isomorphism of Curves.

Published on 19 Jul 2021 - 8:01

score 140 · Answer 4 · 2021-07-22 01:59:37

140

Views

Description Morphisms from Category theory in the language of set theory

Published on 22 Jul 2021 - 1:59

score 81 · Answer 5 · 2021-07-22 13:28:40

81

Views

How to describe all homeomorphisms on $l^2$

Published on 22 Jul 2021 - 13:28

score 11 · Answer 6 · 2021-08-07 14:57:20

11

Views

On the existence of zeroes for non-monomorphic linear operators.

Published on 07 Aug 2021 - 14:57

score 111 · Answer 7 · 2021-09-13 15:49:36

111

Views

"prime" or "indecomposable" morphisms in small category

Published on 13 Sep 2021 - 15:49

score 79 · Answer 8 · 2021-09-24 14:51:19

79

Views

Is a morphism a special case of a function?

Published on 24 Sep 2021 - 14:51

score 65 · Answer 9 · 2021-10-18 18:42:07

65

Views

$M \hookrightarrow M[t^{-1}]$

Published on 18 Oct 2021 - 18:42

score 244 · Answer 10 · 2021-10-31 12:31:23

244

Views

Find a finite morphism $F:X\to\mathbb{P}^k$.

Published on 31 Oct 2021 - 12:31

score 272 · Answer 11 · 2021-11-02 16:15:33

272

Views

What does "up to" mean?

Published on 02 Nov 2021 - 16:15

score 18 · Answer 12 · 2026-03-17 18:39:22

18

Views

Question about morphism of algebras

Published on 17 Mar 2026 - 18:39

score 57 · Answer 13 · 2021-11-06 07:06:55

57

Views

How do I prove the following statement about the kernel?

Published on 06 Nov 2021 - 7:06

score 131 · Answer 14 · 2021-11-12 22:14:35

131

Views

Let $F:\mathcal{A}\to\mathcal{B}$ be a fully faithful covariant functor. Then, if $F(f):F(A_1)\to F(A_2)$ is an isomorphism, so is $f:A_1\to A_2$.

Published on 12 Nov 2021 - 22:14

score 70 · Answer 15 · 2026-02-23 14:09:45

70

Views

Why there is no notion ´bijective´ regarding morphism of schemes?

Published on 23 Feb 2026 - 14:09

List Question

Is a functor that is injective on both objects and morphisms at the same time an embedding functor?

Attempt to define the notion of subobjects

Milne, Elliptic Curves, Theorem 2.1 b), Correctly Stated? - Verifying Something is an Isomorphism of Curves.

Description Morphisms from Category theory in the language of set theory

How to describe all homeomorphisms on $l^2$

On the existence of zeroes for non-monomorphic linear operators.

"prime" or "indecomposable" morphisms in small category

Is a morphism a special case of a function?

$M \hookrightarrow M[t^{-1}]$

Find a finite morphism $F:X\to\mathbb{P}^k$.

What does "up to" mean?

Question about morphism of algebras

How do I prove the following statement about the kernel?

Let $F:\mathcal{A}\to\mathcal{B}$ be a fully faithful covariant functor. Then, if $F(f):F(A_1)\to F(A_2)$ is an isomorphism, so is $f:A_1\to A_2$.

Why there is no notion ´bijective´ regarding morphism of schemes?

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