Question

Recursive square root inside square root problem

score 430 · Answer 1 · 2026-04-12 02:00:06

430

Views

Recursive square root inside square root problem

Published on 12 Apr 2026 - 2:00

score 344 · Answer 2 · 2026-04-15 23:07:54

344

Views

How to find integers $p$ and $q$ such that $(p\sqrt{2}+q)^2=34-24\sqrt{2}$

Published on 15 Apr 2026 - 23:07

score 234 · Answer 3 · 2026-04-14 19:27:41

234

Views

Solve this inequality with nested radicals (possibly by induction)

Published on 14 Apr 2026 - 19:27

score 91 · Answer 4 · 2026-04-16 22:15:46

91

Views

How we can show this: $\sqrt{3+\sqrt{3}}-\sqrt{3-\sqrt{3}}=\sqrt{6-2\sqrt{6}}$

Published on 16 Apr 2026 - 22:15

score 5.4k · Answer 5 · 2026-04-17 02:58:13

5.4k

Views

Showing that $\sqrt[3]{9+9\sqrt[3]{9+9\sqrt[3]{9+\cdots}}} - \sqrt{8-\sqrt{8-\sqrt{8+\sqrt{8-\sqrt{8-\sqrt{8+\cdots}}}}}} = 1$?

Published on 17 Apr 2026 - 2:58

score 94 · Answer 6 · 2026-04-16 15:58:18

94

Views

If $x=-1/4$ does $S=\sqrt{x+\sqrt{x+\sqrt{x+...}}}=1/2$?

Published on 16 Apr 2026 - 15:58

score 391 · Answer 7 · 2026-04-17 03:56:43

391

Views

Show that $\sqrt{a-b\sqrt{a+b\sqrt{a-b\sqrt{a+...}}}}=\sqrt{a-\frac{3b^2}{4}}-\frac{b}{2}$

Published on 17 Apr 2026 - 3:56

score 240 · Answer 8 · 2026-04-15 05:11:50

240

Views

Find $\sqrt[m]{\frac{\sqrt[m]{\frac{\sqrt[m]{\frac{\sqrt[m]{a}}{a}}}{a}}}{\begin{array}{c} a\\\vdots \end{array}}}$

Published on 15 Apr 2026 - 5:11

score 289 · Answer 9 · 2026-04-17 10:02:41

289

Views

Simplify $\frac{2}{\sqrt{4-3\sqrt[4]{5}+2\sqrt{5}-\sqrt[4]{125}}}$

Published on 17 Apr 2026 - 10:02

score 82 · Answer 10 · 2026-04-11 14:07:17

82

Views

How can I figure out a nested radical?

Published on 11 Apr 2026 - 14:07

score 248 · Answer 11 · 2026-04-09 02:40:44

248

Views

How to simplify nested radicals?

Published on 09 Apr 2026 - 2:40

score 2.4k · Answer 12 · 2026-04-13 14:23:43

2.4k

Views

How to prove $\sqrt {a-\sqrt {a+\sqrt {a-\sqrt {a+\sqrt {a-\sqrt {a+\ldots}}}}}}=\frac {\sqrt {4a-3}-1}2$

Published on 13 Apr 2026 - 14:23

score 220 · Answer 13 · 2026-04-17 15:33:53

220

Views

How to solve this radical expression: $\frac 1{xy} \times (\sqrt{xy} - \frac{xy}{x-\sqrt{xy}})\times (\sqrt{xy} + \frac{xy}{x+\sqrt{xy}})$

Published on 17 Apr 2026 - 15:33

score 2.8k · Answer 14 · 2026-04-12 05:41:03

2.8k

Views

Can we make it equal to x?

Published on 12 Apr 2026 - 5:41

score 104 · Answer 15 · 2026-04-17 11:23:18

104

Views

What's equal the below power nested radical?

Published on 17 Apr 2026 - 11:23

List Question

Recursive square root inside square root problem

How to find integers $p$ and $q$ such that $(p\sqrt{2}+q)^2=34-24\sqrt{2}$

Solve this inequality with nested radicals (possibly by induction)

How we can show this: $\sqrt{3+\sqrt{3}}-\sqrt{3-\sqrt{3}}=\sqrt{6-2\sqrt{6}}$

Showing that $\sqrt[3]{9+9\sqrt[3]{9+9\sqrt[3]{9+\cdots}}} - \sqrt{8-\sqrt{8-\sqrt{8+\sqrt{8-\sqrt{8-\sqrt{8+\cdots}}}}}} = 1$?

If $x=-1/4$ does $S=\sqrt{x+\sqrt{x+\sqrt{x+...}}}=1/2$?

Show that $\sqrt{a-b\sqrt{a+b\sqrt{a-b\sqrt{a+...}}}}=\sqrt{a-\frac{3b^2}{4}}-\frac{b}{2}$

Find $\sqrt[m]{\frac{\sqrt[m]{\frac{\sqrt[m]{\frac{\sqrt[m]{a}}{a}}}{a}}}{\begin{array}{c} a\\\vdots \end{array}}}$

Simplify $\frac{2}{\sqrt{4-3\sqrt[4]{5}+2\sqrt{5}-\sqrt[4]{125}}}$

How can I figure out a nested radical?

How to simplify nested radicals?

How to prove $\sqrt {a-\sqrt {a+\sqrt {a-\sqrt {a+\sqrt {a-\sqrt {a+\ldots}}}}}}=\frac {\sqrt {4a-3}-1}2$

How to solve this radical expression: $\frac 1{xy} \times (\sqrt{xy} - \frac{xy}{x-\sqrt{xy}})\times (\sqrt{xy} + \frac{xy}{x+\sqrt{xy}})$

Can we make it equal to x?

What's equal the below power nested radical?

Trending Questions

Popular # Hahtags

Popular Questions