Question

Four dimensional nilpotent real Lie algebras

score 455 · Answer 1 · 2015-12-09 16:08:26

455

Views

Four dimensional nilpotent real Lie algebras

Published on 09 Dec 2015 - 16:08

score 276 · Answer 2 · 2015-12-15 17:44:06

276

Views

Proof about the general form of invariant subspaces of nilpotent operators

Published on 15 Dec 2015 - 17:44

score 186 · Answer 3 · 2015-12-16 07:33:46

186

Views

How to determine if two $6 \times 6$ nilpotent matrices are similar?

Published on 16 Dec 2015 - 7:33

score 392 · Answer 4 · 2015-12-16 17:50:53

392

Views

Are two nilpotent $3\times3$ matrices with rank 2 always similar?

Published on 16 Dec 2015 - 17:50

score 507 · Answer 5 · 2015-12-20 18:03:02

507

Views

$T$ is nilpotent if and only if $[T]_\beta$ is nilpotent.

Published on 20 Dec 2015 - 18:03

score 1.6k · Answer 6 · 2015-12-23 06:30:03

1.6k

Views

Inferring Jordan Block structure from dimension of null spaces

Published on 23 Dec 2015 - 6:30

score 357 · Answer 7 · 2015-12-26 15:13:16

357

Views

Is this a property of nilpotent operators?

Published on 26 Dec 2015 - 15:13

score 393 · Answer 8 · 2015-12-27 14:20:59

393

Views

$R$ semisimple artinian ring $\Rightarrow\varphi(R)$ is such

Published on 27 Dec 2015 - 14:20

score 820 · Answer 9 · 2016-01-06 21:16:50

820

Views

If $A_{n\times n}$ is nilpotent matrix then $\beta = (y, Ay,A^2y, \ldots, A^{k-1}y)$ is the basis of vector space $\mathbb R^n$.

Published on 06 Jan 2016 - 21:16

score 743 · Answer 10 · 2016-01-11 21:41:41

743

Views

Invariant subspace under nilpotent operator

Published on 11 Jan 2016 - 21:41

score 1k · Answer 11 · 2016-01-16 17:05:10

1k

Views

$A$ be $n×n$ matrix $A^{n}=0$ ,$A^{n-1}$ not equal to zero a vector $v$ belongs to R^n.then how to proof {V,AV,...A^(n-1)V} is a basis.

Published on 16 Jan 2016 - 17:05

score 613 · Answer 12 · 2016-01-24 01:50:18

613

Views

Dimension of kernel for nilpotent transformation

Published on 24 Jan 2016 - 1:50

score 664 · Answer 13 · 2016-01-24 20:05:20

664

Views

Dimension of kernel for nilpotent transformation powers

Published on 24 Jan 2016 - 20:05

score 263 · Answer 14 · 2016-02-10 03:27:53

263

Views

nilpotent endomorphism on finitely generated modules over a domain

Published on 10 Feb 2016 - 3:27

score 170 · Answer 15 · 2016-02-11 16:08:37

170

Views

Solution space for quadratic equations with nilpotent matrices

Published on 11 Feb 2016 - 16:08

List Question

Four dimensional nilpotent real Lie algebras

Proof about the general form of invariant subspaces of nilpotent operators

How to determine if two $6 \times 6$ nilpotent matrices are similar?

Are two nilpotent $3\times3$ matrices with rank 2 always similar?

$T$ is nilpotent if and only if $[T]_\beta$ is nilpotent.

Inferring Jordan Block structure from dimension of null spaces

Is this a property of nilpotent operators?

$R$ semisimple artinian ring $\Rightarrow\varphi(R)$ is such

If $A_{n\times n}$ is nilpotent matrix then $\beta = (y, Ay,A^2y, \ldots, A^{k-1}y)$ is the basis of vector space $\mathbb R^n$.

Invariant subspace under nilpotent operator

$A$ be $n×n$ matrix $A^{n}=0$ ,$A^{n-1}$ not equal to zero a vector $v$ belongs to R^n.then how to proof {V,AV,...A^(n-1)V} is a basis.

Dimension of kernel for nilpotent transformation

Dimension of kernel for nilpotent transformation powers

nilpotent endomorphism on finitely generated modules over a domain

Solution space for quadratic equations with nilpotent matrices

Trending Questions

Popular # Hahtags

Popular Questions