List questions from noetherian

Published on 07 Apr 2014 - 14:33

171

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Exercise 6.3 of Matsumura about associated prime ideals

Published on 11 Apr 2014 - 14:59

503

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Noncommutative finitely generated algebras need not be noetherian

Published on 21 Apr 2014 - 15:26

3.8k

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If $M$ is a Noetherian $R$-module, then $R/\text{Ann}(M)$ is a Noetherian ring

Published on 21 Apr 2014 - 18:30

1.8k

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Direct product of Noetherian rings is noetherian

Published on 25 Apr 2014 - 16:08

186

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Approximating modules over complete local rings

Published on 03 May 2014 - 20:30

81

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Equality with powers of an ideal

Published on 04 May 2014 - 7:28

508

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The existence of a projective resolution of M from finite rank free modules

Published on 06 May 2014 - 18:41

189

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Choice of ideal so that localisation of a module must be free?

Published on 11 May 2014 - 19:27

2.2k

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Noetherian ring with finitely many height $n$ primes

Published on 16 May 2014 - 19:34

252

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$A/m^n$ is Artinian for all $n\geq 0$ if $A$ is a Noetherian ring and $m$ maximal ideal.

Published on 21 May 2014 - 4:02

1.3k

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How to prove Ass$(R/Q)=\{P\}$ if and only if $Q$ is $P$-primary when $R$ is Noetherian?

Published on 21 May 2014 - 20:38

2k

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Local ring of Krull dimension zero

Published on 23 May 2014 - 15:13

750

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Examples of Noetherian local rings which are not Gorenstein

Published on 25 Mar 2026 - 17:55

1.1k

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Intersection of ideals is zero then $R$ is Noetherian

Published on 31 May 2014 - 16:52

List Question

Simple Noetherian domain which is not a division ring

Exercise 6.3 of Matsumura about associated prime ideals

Noncommutative finitely generated algebras need not be noetherian

If $M$ is a Noetherian $R$-module, then $R/\text{Ann}(M)$ is a Noetherian ring

Direct product of Noetherian rings is noetherian

Approximating modules over complete local rings

Equality with powers of an ideal

The existence of a projective resolution of M from finite rank free modules

Choice of ideal so that localisation of a module must be free?

Noetherian ring with finitely many height $n$ primes

$A/m^n$ is Artinian for all $n\geq 0$ if $A$ is a Noetherian ring and $m$ maximal ideal.

How to prove Ass$(R/Q)=\{P\}$ if and only if $Q$ is $P$-primary when $R$ is Noetherian?

Local ring of Krull dimension zero

Examples of Noetherian local rings which are not Gorenstein

Intersection of ideals is zero then $R$ is Noetherian

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