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15
Math.TechQA.Club
2013-09-21 02:08:16
581
Views
How to show $\forall g \in G, gHg^{-1} = H \Leftrightarrow \forall g \in G, gHg^{-1} \subseteq H$?
Published on
21 Sep 2013 - 2:08
#abstract-algebra
#group-theory
#normal-subgroups
1.9k
Views
A question based on Normal Subgroups
Published on
10 Oct 2013 - 7:36
#abstract-algebra
#group-theory
#normal-subgroups
14.3k
Views
Example of a Subgroup That Is Not Normal
Published on
19 Oct 2013 - 15:32
#abstract-algebra
#group-theory
#normal-subgroups
7.8k
Views
Non abelian group with normal subgroup
Published on
22 Oct 2013 - 13:40
#abstract-algebra
#group-theory
#examples-counterexamples
#normal-subgroups
2.7k
Views
Subgroups containing kernel of group morphism to an abelian group are normal.
Published on
01 Apr 2026 - 18:49
#abstract-algebra
#group-theory
#abelian-groups
#normal-subgroups
#group-homomorphism
117
Views
Prove that $N \setminus Z(G)\neq \langle e \rangle$.
Published on
02 Nov 2013 - 8:02
#group-theory
#finite-groups
#normal-subgroups
5.4k
Views
Let G be a group. If H is a normal subgroup in G, and K is a normal subgroup of H, when is K a normal subgroup of G?
Published on
08 Nov 2013 - 16:29
#group-theory
#normal-subgroups
62
Views
Group Theory (basic)
Published on
10 Nov 2013 - 2:53
#abstract-algebra
#group-theory
#normal-subgroups
1.8k
Views
Let G be cyclic and let H be a subgroup of G. Show that G/H is cyclic.
Published on
11 Nov 2013 - 1:17
#abstract-algebra
#normal-subgroups
288
Views
isomorphism between two factor groups
Published on
11 Nov 2013 - 22:49
#group-theory
#normal-subgroups
2.3k
Views
Prove or disprove: If H is a normal subgroup of G such that H and G/H are abelian, then G is abelian.
Published on
14 Nov 2013 - 7:17
#group-theory
#abelian-groups
#normal-subgroups
61
Views
Question about proving something about subgroup
Published on
14 Nov 2013 - 10:27
#group-theory
#normal-subgroups
35
Views
Question about describing a sub-group of $S_{\mathbb{R}}$
Published on
14 Nov 2013 - 16:35
#group-theory
#functions
#normal-subgroups
146
Views
$ G/N$ has an element of order $m$ so, $G$ also has an element of order $m$
Published on
15 Nov 2013 - 8:22
#group-theory
#finite-groups
#normal-subgroups
1.3k
Views
find all the members of A4/K
Published on
17 Nov 2013 - 5:49
#abstract-algebra
#group-theory
#normal-subgroups
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