Question

What are the elements of the subgroup of $\mathbb{R}^*$ generated by 7?

score 1.2k · Answer 1 · 2015-10-14 23:30:17

1.2k

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What are the elements of the subgroup of $\mathbb{R}^*$ generated by 7?

Published on 14 Oct 2015 - 23:30

score 439 · Answer 2 · 2026-03-31 22:49:03

439

Views

$k$ cosets of normal subgroup and $k$th power of group element

Published on 31 Mar 2026 - 22:49

score 811 · Answer 3 · 2026-03-28 12:00:32

811

Views

Cross-products of groups and their normal subgroups

Published on 28 Mar 2026 - 12:00

score 1.6k · Answer 4 · 2026-03-30 10:42:41

1.6k

Views

Question about proof that group of order 48 must have a normal subgroup of order 8 or 16

Published on 30 Mar 2026 - 10:42

score 2.2k · Answer 5 · 2026-03-06 01:48:42

2.2k

Views

Let $f \in$ Hom(G,H). Show that Kerf($f$) is a subgroup of $G$ and is normal.

Published on 06 Mar 2026 - 1:48

score 209 · Answer 6 · 2015-10-20 14:45:09

209

Views

Sylow subgroup and normal subgroups

Published on 20 Oct 2015 - 14:45

score 93 · Answer 7 · 2026-03-23 15:23:48

93

Views

Showing that $V \unlhd S_4$, so that $S_4$ is not simple.

Published on 23 Mar 2026 - 15:23

score 64 · Answer 8 · 2026-03-31 09:36:51

64

Views

Normal subgroup of index 2 is the only normal subgroup?

Published on 31 Mar 2026 - 9:36

score 329 · Answer 9 · 2015-10-25 08:41:48

329

Views

Every proper normal subgroup of a $p$-group contains non-trivial central elements

Published on 25 Oct 2015 - 8:41

score 113 · Answer 10 · 2015-10-25 14:00:49

113

Views

Normaliser of a subset is a subgroup.

Published on 25 Oct 2015 - 14:00

score 2.4k · Answer 11 · 2026-04-02 01:26:12

2.4k

Views

Nature of $G$ when $N$ is cyclic, normal subgroup of $G$ and $G/N$ is cyclic

Published on 02 Apr 2026 - 1:26

score 59 · Answer 12 · 2015-10-26 01:18:13

59

Views

Prove that if $H\triangleleft G$, then $H/N$ $\triangleleft$ $G/N$. And vice versa.

Published on 26 Oct 2015 - 1:18

score 196 · Answer 13 · 2015-10-26 13:15:05

196

Views

Give an example of a group that does have subgroups of order 1,2,3,4,5,6, but does not have subgroups of order 7 or 8

Published on 26 Oct 2015 - 13:15

score 260 · Answer 14 · 2026-04-01 00:25:33

260

Views

$g^nH=H$ if $H$ is a nomal subgroup of index $n$

Published on 01 Apr 2026 - 0:25

score 1.1k · Answer 15 · 2026-04-01 00:56:22

1.1k

Views

$A_4$ is not simple

Published on 01 Apr 2026 - 0:56

List Question

What are the elements of the subgroup of $\mathbb{R}^*$ generated by 7?

$k$ cosets of normal subgroup and $k$th power of group element

Cross-products of groups and their normal subgroups

Question about proof that group of order 48 must have a normal subgroup of order 8 or 16

Let $f \in$ Hom(G,H). Show that Kerf($f$) is a subgroup of $G$ and is normal.

Sylow subgroup and normal subgroups

Showing that $V \unlhd S_4$, so that $S_4$ is not simple.

Normal subgroup of index 2 is the only normal subgroup?

Every proper normal subgroup of a $p$-group contains non-trivial central elements

Normaliser of a subset is a subgroup.

Nature of $G$ when $N$ is cyclic, normal subgroup of $G$ and $G/N$ is cyclic

Prove that if $H\triangleleft G$, then $H/N$ $\triangleleft$ $G/N$. And vice versa.

Give an example of a group that does have subgroups of order 1,2,3,4,5,6, but does not have subgroups of order 7 or 8

$g^nH=H$ if $H$ is a nomal subgroup of index $n$

$A_4$ is not simple

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