Question

Why is the infimum of the following relation 1?

score 75 · Answer 1 · 2016-02-14 19:29:27

75

Views

Why is the infimum of the following relation 1?

Published on 14 Feb 2016 - 19:29

score 260 · Answer 2 · 2026-04-06 03:19:26

260

Views

The set of rational numbers has continuum many subsets that are order-wise inequivalent

Published on 06 Apr 2026 - 3:19

score 1k · Answer 3 · 2026-04-06 03:18:09

1k

Views

Sets which are order-isomorphic to the (extended) rationals

Published on 06 Apr 2026 - 3:18

score 277 · Answer 4 · 2026-03-30 22:04:00

277

Views

Subset of rational numbers isomorphic to $\omega^{\omega+1}$

Published on 30 Mar 2026 - 22:04

score 93 · Answer 5 · 2016-02-19 23:27:37

93

Views

Why does $a≤b{\implies}a=b∧a<b$?

Published on 19 Feb 2016 - 23:27

score 94 · Answer 6 · 2016-02-21 01:34:07

94

Views

Order-Preserving Adjunction?

Published on 21 Feb 2016 - 1:34

score 470 · Answer 7 · 2026-03-27 08:55:24

470

Views

Generalized ordering on simplicial complex

Published on 27 Mar 2026 - 8:55

score 55 · Answer 8 · 2026-03-31 22:47:51

55

Views

Is there standard terminology for any or all of these concepts designed to help with thinking about Riemann integrability?

Published on 31 Mar 2026 - 22:47

score 338 · Answer 9 · 2026-03-31 18:21:28

338

Views

How can I prove that if $a^7 = b^7$ then $a=b$, with $ a,b \in \mathbb{Z} $

Published on 31 Mar 2026 - 18:21

score 256 · Answer 10 · 2016-02-27 01:44:30

256

Views

Minimum number of comparisons sufficient to rank any set of $n$ objects?

Published on 27 Feb 2016 - 1:44

score 60 · Answer 11 · 2016-02-27 14:09:17

60

Views

Is there a name for posets in which every nonempty finite subset with a lower bound has an infimum?

Published on 27 Feb 2016 - 14:09

score 512 · Answer 12 · 2016-02-29 05:00:55

512

Views

Prove that if $(A,<)$ is a well ordering, then $(A,<)\nless(A,<)$

Published on 29 Feb 2016 - 5:00

score 900 · Answer 13 · 2016-02-29 10:13:32

900

Views

Suppose $R$ is a partial order on $A$ and $B \subseteq A$. Prove that $R \cap (B \times B)$ a partial order on $B$.

Published on 29 Feb 2016 - 10:13

score 383 · Answer 14 · 2016-02-29 18:59:49

383

Views

The convex combination of two unequal numbers is strictly between them

Published on 29 Feb 2016 - 18:59

score 140 · Answer 15 · 2026-03-31 21:13:35

140

Views

Complete lattices: equivalence between join and meet existence

Published on 31 Mar 2026 - 21:13

List Question

Why is the infimum of the following relation 1?

The set of rational numbers has continuum many subsets that are order-wise inequivalent

Sets which are order-isomorphic to the (extended) rationals

Subset of rational numbers isomorphic to $\omega^{\omega+1}$

Why does $a≤b{\implies}a=b∧a<b$?

Order-Preserving Adjunction?

Generalized ordering on simplicial complex

Is there standard terminology for any or all of these concepts designed to help with thinking about Riemann integrability?

How can I prove that if $a^7 = b^7$ then $a=b$, with $ a,b \in \mathbb{Z} $

Minimum number of comparisons sufficient to rank any set of $n$ objects?

Is there a name for posets in which every nonempty finite subset with a lower bound has an infimum?

Prove that if $(A,<)$ is a well ordering, then $(A,<)\nless(A,<)$

Suppose $R$ is a partial order on $A$ and $B \subseteq A$. Prove that $R \cap (B \times B)$ a partial order on $B$.

The convex combination of two unequal numbers is strictly between them

Complete lattices: equivalence between join and meet existence

Trending Questions

Popular # Hahtags

Popular Questions