Question

$\alpha + \beta=\beta \iff \alpha\omega\le\beta$: is my proof correct?

score 80 · Answer 1 · 2018-05-13 11:58:15

80

Views

$\alpha + \beta=\beta \iff \alpha\omega\le\beta$: is my proof correct?

Published on 13 May 2018 - 11:58

score 110 · Answer 2 · 2018-05-13 12:37:20

110

Views

Does Wolfram's MathWorld describe a different kind of ordinal multiplication?

Published on 13 May 2018 - 12:37

score 284 · Answer 3 · 2018-05-14 09:57:47

284

Views

For what ordinals does $1+\alpha=\alpha$ hold? For what ordinals does $2\alpha=\alpha$ hold?

Published on 14 May 2018 - 9:57

score 96 · Answer 4 · 2018-05-14 20:39:46

96

Views

Ordinal with cofinality $\Omega_\omega$?

Published on 14 May 2018 - 20:39

score 92 · Answer 5 · 2018-05-18 20:01:05

92

Views

$\alpha\ge 2\Rightarrow \alpha^{\beta}\ge\alpha\beta$: is my proof correct?

Published on 18 May 2018 - 20:01

score 690 · Answer 6 · 2018-05-20 15:15:08

690

Views

Is the cardinality of two countably infinite, order-isomorphic sets equal?

Published on 20 May 2018 - 15:15

score 74 · Answer 7 · 2018-05-21 20:14:42

74

Views

Given ordinal $\alpha \geq \omega_1$ does $\alpha \omega_1 = \omega_1 \alpha$

Published on 21 May 2018 - 20:14

score 97 · Answer 8 · 2018-05-22 13:48:35

97

Views

prove that for an ordinal $\alpha \notin \alpha$

Published on 22 May 2018 - 13:48

score 392 · Answer 9 · 2026-03-22 20:58:30

392

Views

Where does this array-based fast-growing function fall in the fast-growing hierarchy, and how does it compare to TREE(n)?

Published on 22 Mar 2026 - 20:58

score 70 · Answer 10 · 2018-05-25 15:56:06

70

Views

In Set Theory what's $0^0$ in terms of ordinals?

Published on 25 May 2018 - 15:56

score 62 · Answer 11 · 2018-05-30 17:31:56

62

Views

If $x$ is a set of ordinals, then $\bigcup x=\alpha$. Why is $x\subseteq \alpha+1$ rather than $\alpha$

Published on 30 May 2018 - 17:31

score 998 · Answer 12 · 2018-05-31 21:58:48

998

Views

Commutativity of Ordinal Multiplication

Published on 31 May 2018 - 21:58

score 350 · Answer 13 · 2018-06-04 09:03:33

350

Views

Prove that $\omega$ is not successor ordinal

Published on 04 Jun 2018 - 9:03

score 978 · Answer 14 · 2018-06-06 08:51:44

978

Views

Proving that the class of all ordinals is well ordered under $\in$

Published on 06 Jun 2018 - 8:51

score 81 · Answer 15 · 2018-06-07 21:04:15

81

Views

Exponentially-closed ordinals

Published on 07 Jun 2018 - 21:04

List Question

$\alpha + \beta=\beta \iff \alpha\omega\le\beta$: is my proof correct?

Does Wolfram's MathWorld describe a different kind of ordinal multiplication?

For what ordinals does $1+\alpha=\alpha$ hold? For what ordinals does $2\alpha=\alpha$ hold?

Ordinal with cofinality $\Omega_\omega$?

$\alpha\ge 2\Rightarrow \alpha^{\beta}\ge\alpha\beta$: is my proof correct?

Is the cardinality of two countably infinite, order-isomorphic sets equal?

Given ordinal $\alpha \geq \omega_1$ does $\alpha \omega_1 = \omega_1 \alpha$

prove that for an ordinal $\alpha \notin \alpha$

Where does this array-based fast-growing function fall in the fast-growing hierarchy, and how does it compare to TREE(n)?

In Set Theory what's $0^0$ in terms of ordinals?

If $x$ is a set of ordinals, then $\bigcup x=\alpha$. Why is $x\subseteq \alpha+1$ rather than $\alpha$

Commutativity of Ordinal Multiplication

Prove that $\omega$ is not successor ordinal

Proving that the class of all ordinals is well ordered under $\in$

Exponentially-closed ordinals

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